HDOJ 1021 Fibonacci Again

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
    int n;
    while(scanf("%d",&n)!=EOF){
        if((n-2)%4==0) printf("yes\n");
        else printf("no\n");
    }
    return 0;
}


你可能感兴趣的:(HDOJ 1021 Fibonacci Again)