Codeforces Round #155 (Div. 2)
第三个题，自己sb不解释啊。。想了1个小时+，愣是没想清楚过程，好在前两个还算比较稳，rating小升，第一次上1600+。。。
第一个题，题意很简单，刚想开敲，发现如果有很多重复的不好哈希，有点激动了，好在想了几分钟后，乱搞一种，边哈希，一边输出的办法，10分钟。
1 #include <cstdio> 2 #include <cstring> 3 #include <string> 4 #include <map> 5 #include <queue> 6 #include <vector> 7 #include <algorithm> 8 #include <iostream> 9 using namespace std; 10 int p[1000000],o[5001]; 11 int main() 12 { 13 int n,i,z; 14 freopen("input.txt","r",stdin); 15 freopen("output.txt","w",stdout); 16 scanf("%d",&n); 17 for(i = 1;i <= 2*n;i ++) 18 { 19 scanf("%d",&p[i]); 20 o[p[i]] ++; 21 } 22 z = 0; 23 for(i = 1;i <= 5000;i ++) 24 { 25 if(o[i]%2 == 1) 26 { 27 z = 1; 28 break; 29 } 30 } 31 if(z) 32 { 33 printf("-1\n"); 34 return 0; 35 } 36 memset(o,0,sizeof(o)); 37 for(i = 1;i <= 2*n;i ++) 38 { 39 if(o[p[i]]) 40 { 41 printf("%d %d\n",o[p[i]],i); 42 o[p[i]] = 0; 43 } 44 else 45 o[p[i]] = i; 46 } 47 return 0; 48 }
第二个题，看懂题，认真一点，就没问题，39分钟AC。
1 #include <cstdio> 2 #include <cstring> 3 #include <string> 4 #include <map> 5 #include <queue> 6 #include <vector> 7 #include <algorithm> 8 #include <iostream> 9 using namespace std; 10 int p[1001]; 11 int mon[14] = {31,28,31,30,31,30,31,31,30,31,30,31}; 12 int sum[14]; 13 int main() 14 { 15 int n,i,j,m,d,q,t; 16 freopen("input.txt","r",stdin); 17 freopen("output.txt","w",stdout); 18 scanf("%d",&n); 19 sum[0] = mon[0]; 20 for(i = 1;i <= 11;i ++) 21 sum[i] = sum[i-1]+mon[i]; 22 for(i = 1;i <= n;i ++) 23 { 24 scanf("%d%d%d%d",&m,&d,&q,&t); 25 for(j = 1;j <= t;j ++) 26 { 27 if(m > 1) 28 p[100+sum[m-2]+d-j] += q; 29 else 30 p[100+d-j] += q; 31 } 32 } 33 int ans = 0; 34 for(i = 1;i <= 1000;i ++) 35 { 36 if(ans < p[i]) 37 ans = p[i]; 38 } 39 printf("%d\n",ans); 40 return 0; 41 }
悲剧啊。。。
1 #include <cstdio> 2 #include <cstring> 3 #include <string> 4 #include <map> 5 #include <queue> 6 #include <vector> 7 #include <algorithm> 8 #include <iostream> 9 using namespace std; 10 char s1[100001],s2[100001]; 11 int o1[301],o2[301],o4[301]; 12 int key[100001]; 13 int Abs(int a) 14 { 15 if(a < 0) 16 return -a; 17 else 18 return a; 19 } 20 int main() 21 { 22 int i,j,len,t,ans = 0; 23 freopen("input.txt","r",stdin); 24 freopen("output.txt","w",stdout); 25 scanf("%s%s",s1,s2); 26 len = strlen(s1); 27 for(i = 0;i <= len-1;i ++) 28 { 29 t = s1[i]; 30 o1[t] ++; 31 t = s2[i]; 32 o2[t] ++; 33 } 34 for(i = 1;i <= 200;i ++) 35 { 36 if(o1[i] != o2[i]) 37 { 38 ans += Abs(o1[i]-o2[i]); 39 } 40 } 41 ans = ans/2; 42 printf("%d\n",ans); 43 for(i = 0;i <= len-1;i ++) 44 { 45 if(o1[s1[i]] > o2[s1[i]]) 46 { 47 for(j = 'A';j <= 'Z';j ++) 48 { 49 if(o1[j] < o2[j]) 50 { 51 if(j < s1[i]) 52 { 53 printf("%c",j); 54 o1[j] ++; 55 o1[s1[i]] --; 56 } 57 else if(o4[s1[i]] == o2[s1[i]]) 58 { 59 printf("%c",j); 60 o1[j] ++; 61 } 62 else 63 { 64 printf("%c",s1[i]); 65 o4[s1[i]] ++; 66 } 67 break; 68 } 69 } 70 if(j == 'Z'+1) 71 printf("%c",s1[i]); 72 } 73 else 74 printf("%c",s1[i]); 75 } 76 return 0; 77 }