1 /* 2 题意:给出一种方案使得abs (A - G) <= 500,否则输出-1 3 贪心:每次选取使他们相差最小的,然而并没有-1:) 4 */ 5 #include <cstdio> 6 #include <cstring> 7 #include <iostream> 8 #include <cmath> 9 #include <algorithm> 10 using namespace std; 11 12 const int MAXN = 1e6 + 10; 13 const int INF = 0x3f3f3f3f; 14 15 int main(void) //Codeforces Round #173 (Div. 2) B. Painting Eggs 16 { 17 // freopen ("B.in", "r", stdin); 18 19 int n; 20 while (scanf ("%d", &n) == 1) 21 { 22 string ans = ""; int sum_a = 0, sum_g = 0; 23 for (int i=1; i<=n; ++i) 24 { 25 int x, y; 26 scanf ("%d%d", &x, &y); 27 if (abs (sum_a + x - sum_g) <= abs (sum_g + y - sum_a)) {ans += "A"; sum_a += x;} 28 else {ans += 'G'; sum_g += y;} 29 } 30 31 cout << ans << endl; 32 } 33 34 return 0; 35 }