2018-08-05 斐波那契数列

纯粹个人记录 题目出处

递归

public  static int Fibonacci(int n ){
        switch (n){
            case 0: return 0;
            case 1: return 1;
            case 2: return 1;
        }
        return Fibonacci(n-1)+Fibonacci(n-2);
    }

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动态规划

public  static int Fibonacci(int n ){
        int f =0,g=1;
        while(n-->0){
            g += f;
            f=g-f;
        }
        return f;
        //return Fibonacci(n-1)+Fibonacci(n-2);
    }