1295. Find Numbers with Even Number of Digits

Given an array nums of integers, return how many of them contain an even number of digits.

 

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:

Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.

 

Constraints:

• 1 <= nums.length <= 500
• 1 <= nums[i] <= 10^5

class Solution {
  public int findNumbers(int[] nums) {
        int cnt = 0;
        for (int n : nums)
            cnt += 1 - Integer.toString(n).length() % 2;
        return cnt;
    }
}

class Solution {
    public int findNumbers(int[] nums) {
        int l = nums.length;
        int res = 0;
        for(int i: nums){
            String t = i + "";
            if(t.length() % 2 == 0) res++;
        }
        return res;
    }
}