266. Palindrome Permutation

Given a string, determine if a permutation of the string could form a palindrome.

For example,
"code" -> False, "aab" -> True, "carerac" -> True.

Solution:hashmap(bucket)count or hashset

Time Complexity: O(N) Space Complexity: O(N)

Solution Code:

class Solution {
    public boolean canPermutePalindrome(String s) {
        Set set=new HashSet();
        for(int i = 0; i < s.length(); ++i){
            if (!set.contains(s.charAt(i)))
                set.add(s.charAt(i));
            else 
                set.remove(s.charAt(i));
        }
        return set.size()==0 || set.size()==1;
    }
}

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