permutations

[leetcode]Permutations

新博文地址：[leetcode]Permutations Permutations Given a collection of numbers, return all possible permutations
huntfor·2014-05-14 10:00

【Leetcode】Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].分析：暂时不用考虑重复元素问题。思路一：排列问题一般可以用递归进行解决，先从序列
bjtu08301097·2014-04-30 14:00

Permutation Sequence

unique permutations.
·2014-04-20 19:00

LeetCode:Permutations, Permutations II(求全排列)

Permutations Given a collection of numbers, return all possible permutations.
·2014-04-13 19:00

LeetCode(Permutations II)

题目要求：Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].思路：跟之前的题目不同之处是这里元素有重复，所以
lqcsp·2014-04-09 12:00

LeetCode(Permutations) 数列的全排列

题目要求：Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].思路：从集合中一次选出每一个元素作为排列的第一个元素，然后对生育的元素
lqcsp·2014-04-09 09:00

[ACM] poj 2369 Permutations (置换群循环节长度）

DescriptionWeremindthatthepermutationofsomefinalsetisaone-to-onemappingofthesetontoitself.Lessformally,thatisawaytoreorderelementsoftheset.Forexample,onecandefineapermutationoftheset{1,2,3,4,5}asfollo
sr19930829·2014-03-31 20:00

Permutations II -- LeetCode

原题链接: http://oj.leetcode.com/problems/permutations-ii/ 这个题跟Permutations非常类似，唯一的区别就是在这个题目中元素集合可以出现重复。
linhuanmars·2014-03-20 01:00

Permutations -- LeetCode

原题链接: http://oj.leetcode.com/problems/permutations/ 这道题跟N-Queens，SudokuSolver，CombinationSum，Combinations
linhuanmars·2014-03-20 00:00

LeetCode Permutations

全排列问题，今天看到微博上有人说清华的研究生复试上机试题有一道全排列问题，貌似学生们回答的不好。想起以前在leetCode上面也刷过全排列问题，就又重新AC了一次。Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2]
worldwindjp·2014-03-18 23:00

Leetcode中的组合排列问题：Permutations，Combinations,Letter Combinations of a Phone Number

1.全组合问题Permutations先固定一个数，把剩下的数继续组合。递归函数的参数有：数组num[]，一个组合list，返回结果lists。
okiwilldoit·2014-03-06 15:00

Leetcode全排列问题

目录1、编号30NextPermutation2、编号44Permutations3、编号45PermutationsII4、编号60PermutationSequence1、编号30 NextPermutationImplementnextpermutation
wangxiaojun911·2014-02-07 01:00

LeetCode OJ:Permutations II

PermutationsII Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].使用next_permuta
starcuan·2014-01-29 16:00

LeetCode OJ:Permutations

Permutations Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations
starcuan·2014-01-29 15:00

UVa 11077 Find the Permutations / 置换

把一个排列p变成1,2,...,n可以反过来看成1,2,...,n到p把p分解乘循环如果一个循环有n个元素需要n-1次交换dp[i][j]=dp[i-1][j]+dp[i-1][j-1]*(i-1);代表i个元素交换j次变成1,2,...,n,的种数对于元素i他可以自己成为一个循环那么交换次数不变种数+1就是dp[i-1][j]               加入前面任意循环的任一个位置有i-1中 
u011686226·2014-01-25 21:00

【LeetCode】Permutations && Permutations II

1、Permutations TotalAccepted:6396TotalSubmissions:20594MySubmissionsGivenacollectionofnumbers,returnallpossiblepermutations.Forexample
u013027996·2014-01-24 14:00

[leetcode]Permutations II

想用递归。。。结果感觉有点麻烦。。。   那要么就用stl的next_permutation吧，，，不过这样好没意思。。。 还是自己实现吧。。。   class Solution { public: bool next_per(vector<int>& num) { int size = num.size();
·2014-01-10 20:00

[leetcode]Permutations

dfs枚举   class Solution { public: unordered_set<int> st; void search(vector<int> &num , vector<vector<int> > &ans , vector<int>& tmp , int
·2014-01-10 19:00

生成所有全排列 非递归和递归实现

Given a collection of numbers, return all possible permutations.
·2014-01-08 17:00

Leetcode: Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].在I的基础上需要去掉重复出现的。classSolution
u013166464·2013-12-31 23:00

Leetcode: Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].以前看MoreWindows的文章，有介绍这个，在此谢过。classSoluti
u013166464·2013-12-31 22:00

LeetCode | Permutations II

题目：Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].思路：与http://blog.csdn.net/l
lanxu_yy·2013-12-24 11:00

LeetCode | Permutations

题目：Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].思路：利用递归的思路完成。每次选择一个数，然后剩余的数来补充剩下的空余位置
lanxu_yy·2013-12-24 10:00

Permutations 排序（有重复数）II @LeetCode

比起http://blog.csdn.net/fightforyourdream/article/details/14217105多加了一个while来去重，发现这个去重方法在另一道题也用过，同样也是DFS里面去重，很好用！另外就是在最前面加了一个sort，因为如果没加，当输入乱序时就会OutputLimitExceed!packageLevel4; importjava.util.ArrayL
hellobinfeng·2013-12-20 14:00

LeetCode Permutations I && II

Permutations Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations
kenden23·2013-12-10 07:00

输出全排列

public class Permutations { public void permute(String value, int startIndex, int endIndex) {
MouseLearnJava·2013-12-09 14:00

Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].DFS的题，感觉有点像是八皇后问题的变形。程序的框架和思想也差不多。publicclassS
marstorm08·2013-12-08 23:53

Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].DFS的题，感觉有点像是八皇后问题的变形。程序的框架和思想也差不多。publicclassS
marstorm08·2013-12-08 23:53

[LeetCode]Permutations,解题报告

前言今天用java写了LeetCodeoj上关于全排列的代码，这个算法之前我用c代码详细的讲解过，想看原理的移步：字符串全排列算法感觉java的集合是神器，而且全排列算法在找工作笔试和面试中经常会出现，所以把java实现的代码也分享以下题目Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]haveth
zinss26914·2013-12-06 10:00

windows 环境下使用GSL

：ComplexNumbers              RootsofPolynomials         SpecialFunctionsVectorsandMatrices          Permutations
Chinamming·2013-12-02 12:00

Permutations II

难度：3Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].求全排列，且不能相同、先排序对于相同的数，我们规定
zhangwei1120112119·2013-11-20 13:00

Permutations

难度：2Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].找到所有排列，DFS，久不写裸搜，居然写错了两次。。。classSolu
zhangwei1120112119·2013-11-20 13:00

全排列生成 Permutations

题目：Givenacollectionofnumbers,returnallpossiblepermutations. Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].思路一（无重复元素）：这是通过交换得到的全排列。classSolution{ pub
luckyjoy521·2013-11-13 18:00

Permutations 排序 @LeetCode

17441117第二种方法比较直观，DFS分成done和rest，每次依次从rest转移一个元素到donepackageLevel3; importjava.util.ArrayList; /** *Permutations
hellobinfeng·2013-11-06 01:00

【LeetCode】Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].Discussjavacode:(codeisthedoc
xiaozhuaixifu·2013-11-05 15:00

LeetCode题解：Permutations I and II

PermutationsGivenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].PermutationsIIGivenacollectionofnu
MagiSu·2013-11-04 02:00

leetcode：Permutations II （序列所有无重复排列）【面试算法题】

题目：Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].题意输出给定序列的所有无重复排列。做法和思路基本和上
zhang9801050·2013-10-29 21:00

集合元素的排列与子集

一、集合的排列      给定一个集合S，含有n个不重复的元素，输出该集合元素的所有排列，leetcode对应题目为：http://oj.leetcode.com/problems/permutations
yutianzuijin·2013-10-26 22:00

leetcode：Permutations （序列所有排列）【面试算法题】

题目：Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].题意输出给定序列的所有排列。用dfs去遍历所有可能的序列，data记录结果
zhang9801050·2013-10-17 15:00

【LeetCode】Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].code:STLmethodandrecursionmethod.classSo
xiaozhuaixifu·2013-10-15 13:00

cf119 div1 a,b,c Permutations AlgoRace Weak Memory

a题:纸上模拟下就知道在b中找一个连续的序列对应a，那么其他后面的值都可以往后或者插入了。直接考虑b中连续的对应a的位置就好了b题：先预处理每辆车的floyd距离然后dp【i】【j】【k】用i辆车，从j到k的最短时间 转移是dp【i】【j】【k】=dp【i-1】【j】【kk】+dp【0】【kk】【k】即类似floyd的转移c题：貌似很多人是二分+spfa或者bfs判断的。。。我开始没想那么多直接一
luyuncheng·2013-10-09 12:00

codeforces 341C Iahub and Permutations(组合数dp)

C.IahubandPermutationstimelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputIahubissohappyaboutinventingbubblesortgraphsthathe'sstayingalldaylongattheofficeandwrit
opm777·2013-10-07 11:00

Leetcode: Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].voidpermute(vector&num,intind
doc_sgl·2013-10-04 23:00

Leetcode: Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].voidget(vector&num,intindex,vector>&solu
doc_sgl·2013-10-04 20:00

CF 341C: Iahub and Permutations

题目链接：http://codeforces.com/contest/341/problem/C题目大意：给定一个含有N个位置的序列，某些位置上的数字已经确定，某些位置上的数字没有确定。求这个序列可能产生多少种错排(a[i]!=i)。算法：这题的做法基本就是DP或容斥。先说一下DP的解法。感谢wuyiqi大牛的耐心讲解。 >_ #include #include #include #include
frog1902·2013-09-02 01:00

[leetcode] Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].classSolution{ public: vector
logarrow·2013-08-27 15:00

[Leetcode] Permutations / Permutations II

Permutations IIMar 17 '124943 / 12877 Given a collection of numbers that might contain duplicates,
cozilla·2013-08-22 15:00

leetcode -- Permutation Sequence

unique permutations.
·2013-08-11 13:00

[leetcode] permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].最简单的当属用递归的方法去解：classSolution{ public: ve
logarrow·2013-08-10 18:00

leetcode -- Permutations II TODO

Given a collection of numbers that might contain duplicates, return all possible unique permutations.
·2013-08-07 10:00
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