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permutation
LeetCode:Next
Permutation
Next
Permutation
TotalAccepted: 70533 TotalSubmissions: 261357 Difficulty: MediumImplementnext
permutation
itismelzp
·
2016-07-01 12:00
LeetCode
array
Coderforces 354Div2
A.Nicholasand
Permutation
timelimitpertest:1secondmemorylimitpertest:256megabytesNicholashasanarrayathatcontainsndistinctintegersfrom1ton.Inotherwords
huayunhualuo
·
2016-06-23 13:00
Codeforces Round #354 (Div. 2)(A && B && C)
传送门A.Nicholasand
Permutation
timelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputNicholashasanarray
qingshui23
·
2016-06-21 18:00
Permutation
Sequence
unique
permutation
s.Bylistingandlabelingallofthe
permutation
sinorder,Wegetthefollowingsequence(ie,fo
EbowTang
·
2016-06-12 22:00
LeetCode
C++
算法
面试
回溯
翻译:字母排序算法解析
原文:Nextlexicographical
permutation
algorithm作者:Nayuki简介假设存在数组(如:[0,3,3,5,8]),现在要生成其所有排列,最好的方法是什么?
田靖荣
·
2016-06-11 00:00
排序
字母排序
面试
算法
STL-String/Vector
好用的STL函数next_
permutation
(a,a+n)atoi("100")//返回值无法判断是正确还是错误strtoi("1020",&str,base);//base是进制数,把第一个非法字符的地址保存在
鬼谷神奇
·
2016-06-08 01:10
Permutation
Sequence
unique
permutation
s.Bylistingandlabelingallofthe
permutation
sinorder,Wegetthefollowingsequence(ie,forn=
yeshiwu
·
2016-06-07 16:00
java
Math
LeetCode
笔试题73. LeetCode OJ (60)
Permutation
Sequence 这个题是求1~n(n[1~9])的数字的全排列的第K个序列。 一般思路是:使用一个计数器,递归去找全排列序列,找到一个计数器加一,一直到第k个。
zr1076311296
·
2016-06-04 14:00
LeetCode
C++
算法
全排列(next_
permutation
)
inti=0;i>p[i]; } sort(p,p+n); do { for(inti=0;i
permutation
liangzhaoyang1
·
2016-06-03 22:00
全排列
Permutation
Sequence
unique
permutation
s.Bylistingandlabelingallofthe
permutation
sinorder,Wegetthefollowingsequence(ie,forn=
无码萌妹码代码
·
2016-05-31 19:39
Leetcode
Permutation
Sequence
unique
permutation
s.Bylistingandlabelingallofthe
permutation
sinorder,Wegetthefollowingsequence(ie,forn=
cmershen
·
2016-05-31 19:00
Next
Permutation
题目原文:Implementnext
permutation
,whichrearrangesnumbersintothelexicographicallynextgreater
permutation
ofnumbers.Ifsucharrangementisnotpossible
cmershen
·
2016-05-31 17:00
Permutation
s II
题目原文:Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleunique
permutation
s.题目大意:接Middle
cmershen
·
2016-05-31 16:00
Permutation
s
题目原文:Givenacollectionofdistinctnumbers,returnallpossible
permutation
s.Forexample,[1,2,3]havethefollowing
permutation
s
cmershen
·
2016-05-31 15:00
【Leetcode】
Permutation
Sequence
题目链接:https://leetcode.com/problems/
permutation
-sequence/题目:Theset [1,2,3,…,n] containsatotalof n!
yeqiuzs
·
2016-05-31 00:00
Leetcode刷题系列(一)Subsets 与
Permutation
Subsets与
Permutation
这两种题型如果用Recursion的方法来解决,其思路是及其相似的。
lingyun_fay
·
2016-05-30 22:26
leetcode
【Leetcode】Next
Permutation
题目链接:https://leetcode.com/problems/next-
permutation
/题目:Implementnext
permutation
,whichrearrangesnumbersintothelexicographicallynextgreater
permutation
ofnumbers.Ifsucharrangementisnotpossible
yeqiuzs
·
2016-05-29 21:00
Codeforces Round #354 (Div. 2)
比赛链接:http://codeforces.com/contest/676A.Nicholasand
Permutation
分析:水题,找到1和n到两边距离的最大值即可。
Yukizzz
·
2016-05-27 22:00
Codeforces Round #354 (Div. 2) A (水题)
A.Nicholasand
Permutation
timelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputNicholashasanarray
liangzhaoyang1
·
2016-05-26 22:00
round
水题
codeforces
2
a
Div.
#354
Nicholas and
Permutation
水题
A.Nicholasand
Permutation
题目连接:http://www.codeforces.com/contest/676/problem/ADescriptionNicholashasanarrayathatcontainsndistinctintegersfrom1ton.Inotherwords
qscqesze
·
2016-05-26 15:00
Codeforces Round #354 (Div. 2)
感觉这次cf代码打得都比较挫,但没想到都能过终测,等了好久的cf,这次时间提早终于也让我水了一次...链接→CodeforcesRound#354(Div.2) ProblemANicholasand
Permutation
Accept
queuelovestack
·
2016-05-26 09:00
ACM
codeforces
Nicholas and
Permutation
(易题)
纪念一下自己差劲的适应能力,cf,要锻炼自己,适应能力很关键!!!#include #include #include #include usingnamespacestd; intmain() { intn,a[105]; scanf("%d",&n); for(inti=1;ia[maxn]) maxn=i; if(a[i]minn) { if(n-maxn>minn-1) printf("
huatian5
·
2016-05-26 02:00
codeforces
Permutation
Sequence.
unique
permutation
s.Bylistingandlabelingallofthe
permutation
sinorder,Wegetthefollowingsequence(ie,forn=
terence1212
·
2016-05-25 10:00
LeetCode
枚举排列
**/ //生成1~n的排列 voidprint_
permutation
(int*A,intn,intcur){ //递归边界 if(cur==n){ for(inti=0;i
q547550831
·
2016-05-22 13:00
ACM
全排列
LeetCode:
Permutation
s II
Permutation
sIITotalAccepted: 71670 TotalSubmissions: 254494 Difficulty: MediumGivenacollectionofnumbersthatmightcontainduplicates
itismelzp
·
2016-05-22 12:00
LeetCode
Permutations
II
snoitatumreP.46
problem:https://leetcode.com/problems/
permutation
s/tips:backtracking,,,
Mhtirogla
·
2016-05-18 21:45
snoitatumreP.46
problem:https://leetcode.com/problems/
permutation
s/tips:backtracking,,,
Mhtirogla
·
2016-05-18 21:45
python中的排列组合方法-itertools模块
>>> import itertools >>> perms = itertools.
permutation
s(['r','e','d']) >>> perms >>> list(perms) [('
qizok
·
2016-05-16 11:10
python
generator
itertools
hdu 4676 Sum Of Gcd 莫队+phi反演
pid=4676DescriptionGivenyouasequenceofnumbera1,a2,...,an,whichisa
permutation
of1...n.Youneedtoanswersomequeries
qscqesze
·
2016-05-14 22:00
leetcode_c++:Next
Permutation
(031)
题目Implementnext
permutation
,whichrearrangesnumbersintothelexicographicallynextgreater
permutation
ofnumbers.Ifsucharrangementisnotpossible
mijian1207mijian
·
2016-05-13 00:00
生成1-n的排列
>t; for(inti=0;i>a[i]; sort(a,a+t); do{ for(inti=0;i
permutation
qq_33901573
·
2016-05-12 20:00
剑指Offer—字符串排列
#include #include usingnamespacestd; voidString
Permutation
(char*pStr,char*pBegin); //字符串排列 v
xiaominkong123
·
2016-05-12 20:00
POJ1731Orders next_
permutation
全排列
OrdersTimeLimit: 1000MS MemoryLimit: 10000KB 64bitIOFormat: %I64d&%I64uDescriptionThestoresmanagerhassortedallkindsofgoodsinanalphabeticalorderoftheirlabels.Allthekindshavinglabelsstartingwiththesamel
wuxiushu
·
2016-05-11 21:00
ACM
poj
POJ1146 ID Codes(next_
permutation
全排列)
IDCodesTimeLimit: 1000MS MemoryLimit: 10000KB 64bitIOFormat: %I64d&%I64uDescriptionItis2084andtheyearofBigBrotherhasfinallyarrived,albeitacenturylate.Inordertoexercisegreatercontroloveritscitizensandt
wuxiushu
·
2016-05-11 20:00
ACM
HDU
HDU 1716 排列2
在STL中,除了next_
permutation
外,还有一个函数prev_
permutation
,两者都是用来计算排列组合的函数。前者是求出下一个排列组合,而后者是求出上一个排列组合。所谓“下一
yangkunpengD
·
2016-05-11 20:00
ACM
STL
HDU解题报告
HDU1716 排列2 next_
permutation
的用法
排列2TimeLimit: 1000MS MemoryLimit: 32768KB 64bitIOFormat: %I64d&%I64uDescriptionRay又对数字的列产生了兴趣: 现有四张卡片,用这四张卡片能排列出很多不同的4位数,要求按从小到大的顺序输出这些4位数。 Input每组数据占一行,代表四张卡片上的数字(0 #include #include #include #inclu
wuxiushu
·
2016-05-11 20:00
ACM
HDU
Permutation
s II
一天一道LeetCode系列(一)题目Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleunique
permutation
s.Forexample
terence1212
·
2016-05-10 16:00
LeetCode
Permutation
s
一天一道LeetCode系列(一)题目Givenacollectionofdistinctnumbers,returnallpossible
permutation
s.Forexample,[1,2,3]
terence1212
·
2016-05-10 14:00
LeetCode
Permutation
s
Givenacollectionof distinct numbers,returnallpossible
permutation
s.Forexample,[1,2,3] havethefollowing
permutation
s
qq_27991659
·
2016-05-09 19:00
Next
Permutation
参考地址 http://www.mamicode.com/info-detail-650903.html首先,关于什么是全排列不做解释。如果一个排列为A,下一个排列为A_NEXT,那么A_NEXT一定与A有尽可能长的公共前缀。看具体例子,一个排列为124653,如何找到它的下一个排列,因为下一个排列一定与124653有尽可能长的前缀,所以,脑洞大开一下,从后面往前看这个序列,如果后面的若干个数字有
agsws
·
2016-05-09 09:00
LeetCode-46&47.
Permutation
s
Givenacollectionof distinct numbers,returnallpossible
permutation
s.Forexample,[1,2,3] havethefollowing
permutation
s
zmq570235977
·
2016-05-07 21:00
LeetCode
hdu 3833 YY's new problem
65536/65536K(Java/Others)TotalSubmission(s):5443 AcceptedSubmission(s):1530ProblemDescriptionGivena
permutation
Pof1toN
xiaojixuansu
·
2016-05-07 20:00
枚举排列
/*利用STL中的next_
permutation
枚举排列*/ #include #include usingnamespacestd; intmain() { intn,s[10]; intcnt
qq_29169749
·
2016-05-07 19:00
[LeetCode]047-
Permutation
s II
题目:Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleunique
permutation
s.Forexample
htx931005
·
2016-05-07 14:00
LeetCode
POJ 2159 Ancient Cipher
(
Permutation
)思路假如只有
Permutation
,那么只需要看每个字符出现个数前后是否相等就可以了。设若只有Substitution,观察每个字符第一次出现时分别映射
sinat_32575459
·
2016-05-07 10:00
poj
[LeetCode]046-
Permutation
s
题目:Givenacollectionofdistinctnumbers,returnallpossible
permutation
s.Forexample,[1,2,3]havethefollowing
permutation
s
htx931005
·
2016-05-06 22:00
LeetCode
Next
Permutation
题目描述:Implementnext
permutation
,whichrearrangesnumbersintothelexicographicallynextgreater
permutation
ofnumbers.Ifsucharrangementisnotpossible
yeshiwu
·
2016-05-06 20:00
java
LeetCode
C++标准库中next_
permutation
和pre_
permutation
实现原理
标准库中next_
permutation
函数:找当前序列中元素排列的下一个排列,按照字典顺序进行排列。比如说数组排列"123",那么它的下一个排列为"132",并且返回true。
yang20141109
·
2016-05-06 17:00
含重复字符的字符串的全排列问题(Java)
publicstaticintcount=0; publicstaticvoidmain(String[]args){ char[]list={'a','b','c'}; char[]list1={'a','b','b'}; //
permutation
baidu_22405691
·
2016-05-05 18:00
Permutation
s i, ii
1.题目描述46Givenacollectionofdistinctnumbers,returnallpossible
permutation
s.Forexample,[1,2,3]havethefollowing
permutation
s
zhyh1435589631
·
2016-05-05 13:00
LeetCode
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