hdu 1021 Fibonacci Again

Fibonacci Again

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 50368    Accepted Submission(s): 23858

Problem Description

There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).

 

Input

Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).

 

Output

Print the word "yes" if 3 divide evenly into F(n).

Print the word "no" if not.

 

Sample Input

   
   
   
   

    
    
    
    0
1
2
3
4
5
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    no
no
yes
no
no
no
   
   
   
   

 

Author

Leojay

学好英文很重要，就是问你这个数列的第n项是否可以被3整除；

#include<iostream>
#include<cstdio>
using namespace std;
int ans[1000000];
int main()
{
    ans[0]=7;
    ans[1]=11;
    for(int i=2;i<1000000;++i)
    {
        ans[i]=(ans[i-1]+ans[i-2])%3;
    }
    int n;
    while(scanf("%d",&n)!=EOF)
    {
        if(ans[n]==0)
            puts("yes");
        else
            puts("no");
    }
    return 0;
}