HDOJ Keep on Truckin' 1037

Keep on Truckin'

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10311    Accepted Submission(s): 7135

Problem Description

Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We're not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

 

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

 

Output

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

 

Sample Input

   
   
   
   

    
    
    
    180 160 170
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    CRASH 160
   
   
   
   

 

Source

South Central USA 2003

 

Recommend

We have carefully selected several similar problems for you:   1064  1038  1056  1012  1036 

重点就一句：if the height of the 18-wheeler is less than the height of each of the underpasses, or:   CRASH X

小于18-Wheeler的就按格式输出~

#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
int main()
{
	int a,b,c;
	while(scanf("%d%d%d",&a,&b,&c)!=EOF){
		if(a<=168)printf("CRASH %d\n",a);
		else if(b<=168)printf("CRASH %d\n",b);
		else if(c<=168)printf("CRASH %d\n",c);
		else printf("NO CRASH\n");
	}
	return 0;
}