早前曾为此问题在CSDN发帖求助(GDI+ 如何使用双缓冲绘制图像),得到了一个GDI+下较可行的方法,虽然绘制效果比直接绘制要好一些,不过还不能跟GDI的双缓冲方式比肩。
/*C++ code*/ RECT rc; GetClientRect(g_hwnd,&rc); Bitmap bmp(int(rc.right),int(rc.bottom)); Graphics bmpGraphics(&bmp); bmpGraphics.SetSmoothingMode(SmoothingModeAntiAlias); /*Drawing on bitmap*/ SolidBrush bkBrush(Color(0,0,0)); bmpGraphics.FillRectangle(&bkBrush,0,0,rc.right,rc.bottom); /*Drawing on DC*/ Graphics graphics(hdc); /*Important! Create a CacheBitmap object for quick drawing*/ CachedBitmap cachedBmp(&bmp,&graphics); graphics.DrawCachedBitmap(&cachedBmp,0,0);
void OnEraseBkGnd(HDC hdc) { //do nothing }
RECT rc; GetClientRect(hwnd,&rc); HDC hMemDc = CreateCompatibleDC(hdc); HBITMAP hBmp = CreateCompatibleBitmap(hdc,rc.right,rc.bottom); HBITMAP hOldBmp = (HBITMAP)SelectObject(hMemDc,hBmp); //在此使用hMemDc进行 GDI 绘制 BitBlt(hdc,0,0,rc.right,rc.bottom,hMemDc,0,0,SRCCOPY); SelectObject(hMemDc,hOldBmp); DeleteObject(hBmp); DeleteObject(hMemDc);