GNU make manual 翻译( 一百七十九)

继续翻译

   As this example illustrates, conditionals work at the textual level:

the lines of the conditional are treated as part of the makefile, or

ignored, according to the condition.  This is why the larger syntactic

units of the makefile, such as rules, may cross the beginning or the

end of the conditional.



   When the variable `CC' has the value `gcc', the above example has

this effect:



     foo: $(objects)

             $(CC) -o foo $(objects) $(libs_for_gcc)



When the variable `CC' has any other value, the effect is this:



     foo: $(objects)

             $(CC) -o foo $(objects) $(normal_libs)



   Equivalent results can be obtained in another way by

conditionalizing a variable assignment and then using the variable

unconditionally:



     libs_for_gcc = -lgnu

     normal_libs =



     ifeq ($(CC),gcc)

       libs=$(libs_for_gcc)

     else

       libs=$(normal_libs)

     endif



     foo: $(objects)

             $(CC) -o foo $(objects) $(libs) 

正如这个例子所揭示的那样，条件式在文本层面上工作：条件式的行被当作makefile的一部分，或者被忽略，这取决于条件本身。这就是为什么makefile中的大一些的语法单位，例如规则，可以跨越条件式的开始或终了之处。

当变量CC拥有值gcc， 上述的例子有如下的效果：

foo: $(objects)
$(CC) -o foo $(objects) $(libs_for_gcc)

如果变量 CC 有其他的值，则效果如下：

foo: $(objects)
$(CC) -o foo $(objects) $(normal_libs)

用另外的方法可以得到同样的结果--把一个对变量的赋值进行条件化，然后使用此变量。

libs_for_gcc = -lgnu
normal_libs =

ifeq ($(CC),gcc)
libs=$(libs_for_gcc)
else
libs=$(normal_libs)
endif

foo: $(objects)
$(CC) -o foo $(objects) $(libs)

后文待续