【xml]: Read XML with Namespace resolution using XLinq.XElement

http://www.codeproject.com/KB/linq/xelementns.aspx

 

 

  string myxml =
             @" <root>
                <one xmlns:a='http://rediff.com'>
                    <a:oneone  sequenceId= '11' xmlns:b='http://yahoo.com'>
                        <b:id>1</b:id>
                        <b:name></b:name>
                    </a:oneone>
                    <a:twotwo xmlns:b='http://orkut.com'>
                        <b:id>1</b:id>
                        <b:name></b:name>
                    </a:twotwo>
                </one>
              </root> ";

          XNamespace nsr =  " http://rediff.com ";
          XNamespace nsy =  " http://yahoo.com ";
       
            XElement elem = XElement.Parse(myxml);   

             string t = elem.Element( " one ").Element(nsr +  " oneone ").Element(nsy +  " id ").Value;

            string sequenceId = elem.Element( " one ").Element(nsr +  " oneone ").Attribute( " sequenceId ").Value;


           XDocument doc =  new XDocument();
           doc = XDocument.Parse(myxml);

           XElement docElement = doc.Descendants(nsr +  " oneone ").FirstOrDefault();

            string t1 = docElement.Element(nsr +  " oneone ").Element(nsy +  " id ").Value;

            string sequenceId1 = docElement.Element(nsr +  " oneone ").Attribute( " sequenceId ").Value;