LeetCode1.4

Palindrome Number

LeetCode1.4_第1张图片
Screen Shot 2019-01-04 at 10.48.41 PM.png

答案:

class Solution:
    def isPalindrome(self, x):
        """
        :type x: int
        :rtype: bool
        """
        orig = x
        rev = 0
        if x >= 0:
            while x > 0:
                dig = x % 10
                rev = rev * 10 + dig
                x = x // 10
            if rev == orig:
                return True 
            else:
                return False
        else: 
            return False

你可能感兴趣的:(LeetCode1.4)