sicp

Pascal's triangle in Haskell

SICP中考题1.2->1.12是关于Pascal'striangle，如下图所示，初中数学就学过了。  
bookjovi·2012-02-14 12:00

PerferenceActivity用法

PerferenceActivity是什么，看下面的截图：           Android系统截图（左）               MusicPlayerSetting截图(右）        好了
zyfromcq·2012-02-10 10:00

java解析命令行参数（common-cli）

  import org.apache.commons.cli.CommandLineParser; import org.apache.commons.cli.BasicParser;
heipark·2012-02-08 12:00

[PhoneGap]音乐播放器Android版

PhoneGap #spspan{font-size:15px;color:green;} button{height:70px;width:120px;} Musicplayer
quzishen·2012-02-07 09:00

SICP: Metacircular Evaluator

  SICP 的经典就不用说了，有史以来最值得一读的编程语言书目。
bookjovi·2012-02-03 16:00

jasypt java加密包

org.jasypt.digest.StandardStringDigester; import org.jasypt.encryption.pbe.StandardPBEStringEncryptor; import org.jasypt.util.password.BasicPasswordEncryptor
mimimao0901·2012-02-02 16:00

Android之PreferenceActivity

PerferenceActivity是什么，看下面的截图：Android系统截图（左）MusicPlayerSetting截图(右）好了，我们看到Android系统本身就大量用到了PreferenceActivity
fengkuanghun·2012-02-01 17:00

Android成长之路-音乐播放器的实现

 strings.xmlviewplain          MusicPlayer      曲目      播放      暂停      继续      重置      停止      选择      
云端的Android·2012-01-03 00:00

Android成长之路-音乐播放器的实现

strings.xml MusicPlayer 曲目 播放 暂停 继续 重置 停止 选择 媒体文件不存在 SDcard不存在    main.xml />
like7xiaoben·2012-01-02 19:00

JAVA中Swing组件上绘图机制举例

AprogramwhichdemonstratesthebasicpaintmechanismforSwingcomponents(JPanelforexample).packagecom.han;
Gaowen_HAN·2012-01-02 03:00

web 播放器 兼容ff，ie6 7 8

web播放器functionmusicPlayer(src){varhtml='';html+='';//连接地址做好用标准的url地址。
liuensong·2011-12-27 09:00

android popwindow 解决opengl层叠上面的ui被覆盖的现象

1.初始化ContextmContext=SDMusicPlayBackActivity.this;        LayoutInflatermLayoutInflater=(LayoutInflater
hellolinshoujie·2011-12-22 14:00

[sicp 第一章练习题]

  scheme编程环境：       DrRacket;   SICP第一章讲述：过程抽象。主要训练程序员过程抽象的思维。
pengpeng·2011-12-16 10:00

[读书]

        正在看<计算机程序的构造和解释》简称：SICP; 边看边做练习题。第二章快看完了。这本书试图逐步培养我们：过程抽
pengpeng·2011-12-13 20:00

sicp 2.50

Exercise 2.50.  Define the transformation flip-horiz, which flips painters horizontally, and transformations that rotate painters counterclockwise by 180 degrees and 270 degrees.  
Bloodwolf·2011-12-06 15:00

sicp 2.49

Exercise 2.49.  Use segments->painter to define the following primitive painters: a.  The painter that draws the outline of the designated frame. b.  Th
Bloodwolf·2011-12-06 15:00

播放音乐

pathForResource:@"startLogo"ofType:@"mp3"];    NSURL*musicURL=[[NSURLalloc]initFileURLWithPath:musicFilePath]; musicPlayer
zhouhui2315·2011-12-05 10:00

对SCHEME的一些理解（2）

平时抽空看看SICP，主要是为了理解一些UNIX设计问题，另外也能揣摩最早一批计算机黑客的技术发展历程，UNIX将一切都是文件，一切最好都用文本的思想全面贯彻到系统设计中，想要领悟其哲学，必定得掌握最接近机器模型的
effulgent·2011-12-04 18:00

Ubuntu + Eclipse + GTK环境搭建

二、GTK（有时间补）三.创建工程 新建projectnew->cproject,projecttype选择HelloworldANSIcproject,然后按如下步骤配置：  在project->properties
LeisureLife·2011-12-03 14:00

IA32寄存器

Basicprogramexecutionregisters(基本的编程寄存器)包含8个通用寄存器，6个段寄存器，一个程序状态寄存器和一个指令指针寄存器。
mcgrady_tracy·2011-12-02 14:00

sicp 2.48

Exercise 2.48.  A directed line segment in the plane can be represented as a pair of vectors -- the vector running from the origin to the start-point of the segment, and the vector running f
Bloodwolf·2011-11-28 18:00

sicp 2.47

  Exercise 2.47.  Here are two possible constructors for frames:   (define (make-frame origin edge1 edge2)  (list origin edge1 edge2
Bloodwolf·2011-11-28 18:00

sicp 2.46

Exercise2.46.  Atwo-dimensionalvector v runningfromtheorigintoapointcanberepresentedasapairconsistingofan x-coordinateanda y-coordinate.Implementadataabstractionforvectorsbygivingaconstructor make-vec
Bloodwolf·2011-11-28 17:00

sicp 2.45

  Exercise 2.45.  Right-split and up-split can be expressed as instances of a general splitting operation. Define a procedure splitwith the property that evaluating
Bloodwolf·2011-11-28 17:00

sicp 2.44

Exercise 2.44.  Define the procedure up-split used by corner-split. It is similar to right-split, except that it switches the roles ofbelow and beside.  
Bloodwolf·2011-11-28 17:00

Jquery调用webservice

   ///   [WebService(Namespace="http://tempuri.org/")]   [WebServiceBinding(ConformsTo=WsiProfiles.BasicProfile1
peitianfang·2011-11-28 15:49

web service 开源项目比较

主要特性l支持Webservice标准：包括SOAP,theBasicProfil
yingtju·2011-11-25 16:09

sicp 2.43

Exercise 2.43.  Louis Reasoner is having a terrible time doing exercise 2.42. His queens procedure seems to work, but it runs extremely slowly. (Louis never does manage to
Bloodwolf·2011-11-25 14:00

sicp 2.42

Exercise2.42.   Figure2.8:  Asolutiontotheeight-queenspuzzle. The ``eight-queenspuzzle''askshowtoplaceeightqueensonachessboardsothatnoqueenisincheckfromanyother(i.e.,notwoqueensareinthesamerow,column,
Bloodwolf·2011-11-25 13:00

根据音乐文件和LRC文件的绝对路径下载到sdcard指定目录中

/** *下载音乐文件到指定目录 *@parammusicPath *@parammusicName *@paramsingerName */ publicvoiddownloadMusic
sunlips·2011-11-23 21:00

sicp 2.41

Exercise 2.41.  Write a procedure to find all ordered triples of distinct positive integers i, j, and k less than or equal to a given integer n that sum to a gi
Bloodwolf·2011-11-21 16:00

sicp 2.40

Exercise 2.40.  Define a procedure unique-pairs that, given an integer n, generates the sequence of pairs (i,j) with 1< j< i< n. Useunique-pairs t
Bloodwolf·2011-11-21 11:00

用Java把Kugou下载的音乐进行整理

tntxia * */ public class MusicManager { /** * 音乐文件转移 * @param kugouPath * @param musicPath
tntxia·2011-11-20 18:00

用Java把Kugou下载的音乐进行整理

tntxia * */ public class MusicManager { /** * 音乐文件转移 * @param kugouPath * @param musicPath
tntxia·2011-11-20 18:00

squid 添加 用户认证 域名认证

--enable-basic-auth-helpers=NCSA'完成后，编译squid.conf加入：#定义了认证方式为basic，认证程序的路径和认证程度需要读取的帐户文件auth_parambasicprogram
jafyoo·2011-11-19 18:53

Useful Links

1.classicprojects:1.         http://www.asp.net/downloads/starter-kits/small-business2.         
任永娟2011·2011-11-18 17:23

sicp 2.39

  Exercise 2.39.   Complete the following definitions of reverse (exercise 2.18) in terms of fold-right and fold-left from exercise 2.38:  
Bloodwolf·2011-11-18 01:00

sicp 2.38

Exercise 2.38.  The accumulate procedure is also known as fold-right, because it combines the first element of the sequence with the result of combining all the elements to
Bloodwolf·2011-11-17 19:00

sicp 2.37

Exercise2.37.  Supposewerepresentvectors v =(vi)assequencesofnumbers,andmatrices m =(mij)assequencesofvectors(therowsofthematrix).Forexample,thematrix isrepresentedasthesequence ((1234)(4566)(6789)).W
Bloodwolf·2011-11-17 18:00

sicp 2.26

  Exercise 2.36.  The procedure accumulate-n is similar to accumulate except that it takes as its third argument a sequence of sequences, which are all assumed to h
Bloodwolf·2011-11-17 17:00

sicp 2.35

Exercise 2.35.  Redefine count-leaves from section 2.2.2 as an accumulation:   (define (count-leaves t)  (accumulate <??> &l
Bloodwolf·2011-11-17 17:00

sicp 2.34

 Exercise2.34.  Evaluatingapolynomialin x atagivenvalueof x canbeformulatedasanaccumulation.Weevaluatethepolynomial usingawell-knownalgorithmcalled Horner'srule,whichstructuresthecomputationas Inother
Bloodwolf·2011-11-17 16:00

YCSB%e6%b5%8b%e8%af%95hbase

所以一定要耐着性子看英文，开个词霸，google翻译从gettingstarted开始obtainYCSBsource首先是下载一个压缩包，或者安装git(类似svn)下载源代码，再buildbuildthebasicpackage
sslf·2011-11-16 21:00

sicp 2.33

Exercise 2.33.  Fill in the missing expressions to complete the following definitions of some basic list-manipulation operations as accumulations:   (define (map p s
Bloodwolf·2011-11-16 15:00

sicp 2.32

Exercise 2.32.  We can represent a set as a list of distinct elements, and we can represent the set of all subsets of the set as a list of lists. For example, if the set is (1&n
Bloodwolf·2011-11-16 15:00

sicp 2.31

Exercise 2.31.  Abstract your answer to exercise 2.30 to produce a procedure tree-map with the property that square-tree could be defined as    
Bloodwolf·2011-11-16 14:00

sicp 2.30

Exercise 2.30.  Define a procedure square-tree analogous to the square-list procedure of exercise 2.21. That is, square-list should behave as follows:
Bloodwolf·2011-11-16 14:00

sicp 2.29

  Exercise 2.29.  A binary mobile consists of two branches, a left branch and a right branch. Each branch is a rod of a certain length, from which hangs either a weight or another bina
Bloodwolf·2011-11-16 13:00

mark 的总结开发笔记

pathForResource:@"startLogo"ofType:@"mp3"];NSURL*musicURL=[[NSURLalloc]initFileURLWithPath:musicFilePath];musicPlaye
feipigwang·2011-11-04 14:00

lambda过程作为返回值的例子-分析，及一个作用域的例子

lambda过程作为返回值的例子-分析，及一个作用域的例子1.昨天的例子的分析昨天整完lambda过程作为返回值的例子就被二猫叫走了，没来得及分析.以下是分析及另一个的例子（似乎出自SICP，记不大清了
younggift·2011-11-02 23:00
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