permutations

Python 排列组合的计算

fromscipy.specialimportcomb,perm>>perm(3,2)6.0>>comb(3,2)3.02.调用itertools获取排列组合的全部情况数>>fromitertoolsimportcombinations,permutations
Inside_Zhang·2016-07-04 23:13

Permutations II

题目原文：Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.题目大意：接Middle-题目24，这回数组元素允许重复，还是求所有可能的排列情况。题目分析：方法一：（很慢的朴素解法）首先构造一个hashMap，统计每个元素出现的次数，然后开始回溯，先统计这个元素在hashMa
cmershen·2016-05-31 16:00

Permutations

题目原文：Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].题目大意：给一个没有重复数字的数组，求所有可能的排列情况。题目分析
cmershen·2016-05-31 15:00

LeetCode:Permutations II

PermutationsIITotalAccepted: 71670 TotalSubmissions: 254494 Difficulty: MediumGivenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowin
itismelzp·2016-05-22 12:00

snoitatumreP.46

problem:https://leetcode.com/problems/permutations/tips:backtracking,,,
Mhtirogla·2016-05-18 21:45

snoitatumreP.46

problem:https://leetcode.com/problems/permutations/tips:backtracking,,,
Mhtirogla·2016-05-18 21:45

python中的排列组合方法-itertools模块

>>> import itertools >>> perms = itertools.permutations(['r','e','d']) >>> perms >>> list(perms) [('
qizok·2016-05-16 11:10

Permutations II

一天一道LeetCode系列（一）题目Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[1,1,2],[1,2,1],and[2,1,1].（二）解题求全排列数。具体
terence1212·2016-05-10 16:00

Permutations

一天一道LeetCode系列（一）题目Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].（二）解题求全排列数。具体思路可以参考
terence1212·2016-05-10 14:00

Permutations

Givenacollectionof distinct numbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].【思路】求给定向量数组所有元素的全排列问题。n个元素有n!种
qq_27991659·2016-05-09 19:00

LeetCode-46&47.Permutations

Givenacollectionof distinct numbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].publicclassSolution { publicIL
zmq570235977·2016-05-07 21:00

[LeetCode]047-Permutations II

题目：Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[1,1,2],[1,2,1],and[2,1,1].Solution：直接运用nextPermutation的
htx931005·2016-05-07 14:00

[LeetCode]046-Permutations

题目：Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].Solutions:思路1：比较容易想到，固定住第一位的数，然后全排列
htx931005·2016-05-06 22:00

Permutations i, ii

1.题目描述46Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].47Givenacollectionofnumberstha
zhyh1435589631·2016-05-05 13:00

Permutations

题目：Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].集合中的元素没有重复的。。。解法一：利用STL中的next_permu
chengyu779394084·2016-04-29 18:00

leetcode46/47-Permutations I/II(全排列问题)

1、Permutations问题描述：Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]
will130·2016-04-28 23:00

Permutations

HappyPMPisfreshmanandheislearningaboutalgorithmicproblems.Heenjoysplayingalgorithmicgamesalot.OneoftheseniorsgaveHappyPMPanicegame.Heisgiventwopermutationsofnumbers1throughnandisaskedtoconvertthefirst
f_zyj·2016-04-22 19:00

自定义序列顺序思想 Permutations

PermutationsTimeLimit:2000msMemoryLimit:262144KB64-bitintegerIOformat: %I64d     Javaclassname: (Any)Submit Status PID:20924HappyPMPisfreshmanandheislearningaboutalgorithmicproblems.Heenjoysplayingalg
yuan_jlj·2016-04-21 15:00

Permutations

I.PermutationsTimeLimit:2000msMemoryLimit:262144KB64-bitintegerIOformat:%I64d    Javaclassname:(Any)SubmitStatusPID:20924HappyPMPisfreshmanandheislearningaboutalgorithmicproblems.Heenjoysplayingalgori
wanghandou·2016-04-20 20:00

Permutations

HappyPMPisfreshmanandheislearningaboutalgorithmicproblems.Heenjoysplayingalgorithmicgamesalot.OneoftheseniorsgaveHappyPMPanicegame.Heisgiventwopermutationsofnumbers 1 through n andisaskedtoconvertthef
menxiaoyuan·2016-04-20 14:00

[LeetCode]Permutation全排列和去重全排列

一、问题描述：借助这道题总结一下全排列问题吧https://leetcode.com/problems/permutations/Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample
CristianoJason·2016-04-20 14:34

[LeetCode]Permutation全排列和去重全排列

一、问题描述：借助这道题总结一下全排列问题吧https://leetcode.com/problems/permutations/Givenacollectionof distinct numbers,
CristianoJason·2016-04-20 14:00

leetcode: Permutations II

问题描述：Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1]. 原问题链接：https://leetcode.
frank-liu·2016-04-19 22:00

Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[1,1,2],[1,2,1],and[2,1,1].#include #include usingnamespace
github_34333284·2016-04-17 09:00

leetcode——47——Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[1,1,2],[1,2,1],and[2,1,1].classSolution{ public: vector>pe
happyxuma1991·2016-04-16 20:00

leetcode——46——Permutations

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].方法一：classSolution{ public: vector>perm
happyxuma1991·2016-04-16 19:00

Permutations

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].Classicalbacktrack.Inordertomaketheout
github_34333284·2016-04-14 05:00

Permutations 的两种解法及注释、分析

46.PermutationsGivenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].【分析】实现全排列，一般有两种思路，一是“递归
Jin_Kwok·2016-04-05 22:56

Permutations 的两种解法及注释、分析

46.Permutations Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations
Jin_Kwok·2016-04-05 22:00

Permutations

Givenacollectionof distinct numbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].classSolution{ public: vector>
u014568921·2016-03-31 21:00

Permutations II [Leetcode 解题报告]

returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations: [1,1,2],[1,2,1],and[2,1,1].这个题跟Permutations
zhouyusong_bupt·2016-03-22 10:00

Permutations [Leetcode 解题报告]

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations: [1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].关于这个题方法很多，我在这里挑了两种常用的：一、递归实现，每次从现有的串中
zhouyusong_bupt·2016-03-22 10:00

Permutations II | Java最短代码实现

与 46.Permutations不同的是本题数组中的元素可能重复。为此增加了一个记录数组visit。重点在于要能理解!
happyaaaaaaaaaaa·2016-03-20 21:00

46 - Permutations（全排列和递归）

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].Subscribetoseewhichcompaniesaskedthisq
hellochenlu·2016-03-03 10:00

Permutations II

只比1多了一句话if(i>0&&used[i-1]==true&&nums[i]==nums[i-1]){ continue; }  1publicList>permute(int[]nums){ 2List>res=newArrayList>(); 3if(nums==null||nums.length==0){ 4returnres; 5} 6Arrays.sort(nums);
warmland·2016-02-29 04:00

Permutations

 和combinations比起来，需要多加一个used的数组标记这个数字有没有被用过。1publicList>permute(int[]nums){ 2List>res=newArrayList>(); 3if(nums==null||nums.length==0){ 4returnres; 5} 6boolean[]used=newboolean[nums.length]; 7he
warmland·2016-02-29 04:00

Permutations II 解题报告

题目链接：https://leetcode.com/problems/permutations-ii/Givenacollectionofnumbersthatmightcontainduplicates
qq508618087·2016-02-21 11:00

DFS + BackTracking

Combinationsum1combinationsum2combinationsum3然后是Permutationpermutation2http://www.shuatiblog.com/blog/2014/05/14/Permutations-II
伊萨卡钢琴家·2016-02-14 12:28

Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].classSolution{ public: void
walkwalkwalk·2016-02-07 17:00

Permutations

Givenacollectionof distinct numbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].classSolution{ public: void_
walkwalkwalk·2016-02-07 17:00

Permutations II

题目链接：https://leetcode.com/problems/permutations-ii/题目描述：全排列问题。但是数组中可能包含重复元素，所以要避免解集包含重复组合的情况。
codeTZ·2016-02-06 20:00

Permutations

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].回溯采用交换元素的方法，元素1依次和元素n(n>1)交换同理，元素2依次和元
偏爱纯白色·2016-02-05 16:00

Permutations

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].全排列的问题，同样用回溯法，回溯的边界条件我们可以通过每个结果的长度来判断，
KickCode·2016-01-31 12:04

Permutations II

returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[1,1,2],[1,2,1],and[2,1,1].与Permutations
KickCode·2016-01-31 12:04

UVA 11925 - Generating Permutations

这道题要反方向思考，把题中给的序列转为升序序列，运用冒泡排序，但要注意特殊情况，当序列中的第二个数字为1时，直接把数字从序列尾放到序列头。#include #include #include #include usingnamespacestd; dequenum; vectorans; intn; booljudge() { for(inti=1;i>n&&n) { num.clear();
qq_26122039·2016-01-29 21:00

Permutations

Givenacollectionof distinct numbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].分析:采用从nums[0..i-1]递推出nums[0..i
u010339647·2016-01-27 15:00

康托展开+线段树 Codeforces501D Misha and Permutations Summation

传送门：点击打开链接题意：求两个排列的次序相加取模n！后，得到新的次序，然后输出这个次序对应的排列思路：康托展开+逆展开+高精度。康托展开其实是个求逆序对的过程，逆展开实际上是一个找第k大的过程，都可以使用线段树来完成因为数字非常大，所以肯定是要用高精度的，但是这里的高精度很特别，不是使用十进制的高精度，而是使用阶乘进制的高精度，这样就可以和康托展开和逆展开完美的结合起来了。#include #i
qwb492859377·2016-01-16 19:00

Permutations 解题报告

题目链接：https://leetcode.com/problems/permutations/Givenacollectionof distinct numbers,returnallpossiblepermutations.Forexample
qq508618087·2016-01-14 16:00

Permutations II

https://leetcode.com/problems/permutations-ii/这道题惊讶了一下，竟然超过了百分之94的cpp提交思路很简单next_permutation就行了。
u011026968·2016-01-11 23:00

Permutations DFS

https://leetcode.com/problems/permutations/这道题没啥说的暴力DFS搞，也可以next_permutation#include #include #include
u011026968·2016-01-11 23:00
上一页 9 10 11 12 13 14 15 16 下一页
按字母分类： ABCDEFGHIJKLMNOPQRSTUVWXYZ其他