permutation

【splay tree】 UVA 11922 Permutation Transformer

题目中只有一种操作，把一段区间翻转加到序列后面。。伸展树虽然在区间合并和区间会破坏序列的绝对关系，但是在各种操作中序列的中序遍历是不变的。。。因此我们可以维护一颗伸展树。。然后打上lazy标记，最后求一下最终序列就行了。。。#include #include #include #include #include #include #include #include #include #includ
blankcqk·2014-07-30 17:00

POJ 1731 Orders(STL运用）

next_permutation函数很给力。。
u013013910·2014-07-30 15:00

leetcode Next Permutation(*)

Implementnextpermutation,whichrearrangesnumbersintothelexicographicallynextgreaterpermutationofnumbers.Ifsucharrangementisnotpossible
star_liux·2014-07-28 19:00

Permutation（线段树 + 单点更新）

ProblemFPermutationInput: StandardInputOutput: StandardOutput GivenNandKfindtheN’thpermutationoftheintegersfrom1toKwhenthosepermutationsarelexicographicallyordered
Simone_chou·2014-07-28 09:00

HDU1027 Ignatius and the Princess II 【next_permutation】【DFS】

IgnatiusandthePrincessIITimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):4571    AcceptedSubmission(s):2733ProblemDescriptionNowourherofindsthedoortotheBEe
u012846486·2014-07-21 22:00

STL 源码剖析 算法 stl_algo.h -- pre_permutation

本文为senlie原创，转载请保留此地址：http://blog.csdn.net/zhengsenliepre_permutation---------------------------------
zhsenl·2014-07-20 18:00

poj 2369 Permutations 置换水题

找循环节求lcm就够了，若答案是12345应该输出1，被坑了下。#include #include #include #include #include #include usingnamespacestd; #defineINF0x3FFFFFF #defineMAXN2222 #defineeps1e-6 inta[MAXN],p[MAXN],b[MAXN],vis[MAXN]; intgcd
t1019256391·2014-07-20 16:00

STL 源码剖析 算法 stl_algo.h -- next_permutation

本文为senlie原创，转载请保留此地址：http://blog.csdn.net/zhengsenlienext_permutation--------------------------------
zhsenl·2014-07-19 19:00

[CodeForces 285D Permutation Sum] (搜索）

题目链接：http://codeforces.com/problemset/problem/285/D题目大意：有序列a，b。其中长度均为N，而a1,a2,a3.....an各不相同，且都属于[1,n]。b也是。现在有一个操作，ci = ((ai - 1 + bi - 1) mod n) + 1 (1 ≤ i ≤ n).从而生成一个新的序列C。且使得C也符合上述序列的要求。问a,b有多少种不同的选
SIOFive·2014-07-19 14:00

Next Permutation

这道题是给定一个数组和一个排列，求下一个排列。算法上其实没有什么特别的地方，主要的问题是经常不是一见到这个题就能马上理清思路。下面我们用一个例子来说明，比如排列是(2,3,6,5,4,1)，求下一个排列的基本步骤是这样：1)先从后往前找到第一个不是依次增长的数，记录下位置p。比如例子中的3，对应的位置是1;2)接下来分两种情况：(1)如果上面的数字都是依次增长的，那么说明这是最后一个排列，下一个就
okiwilldoit·2014-07-16 11:00

next_permutation函数

blog.sina.com.cn/s/blog_9f7ea4390101101u.html这是一个求一个排序的下一个排列的函数，可以遍历全排列,要包含头文件下面是以前的笔记  与之完全相反的函数还有prev_permutation
u013263923·2014-07-14 16:00

LeetCode Permutation Sequence

uniquepermutations.Bylistingandlabelingallofthepermutationsinorder,Wegetthefollowingsequence(ie,forn=
xyzchenzd·2014-07-13 14:00

[LeetCode] Permutations II

vector>permuteUnique(vector&num){ vector>permutations; if(num.size()>permutationsWithoutLastNum=permuteUnique
HQBUPT·2014-07-12 22:00

[LeetCode] Permutation

vector>permute(vector&num){ vector>permutations; if(num.size()>permutationsWithoutLastNum=permute(num
HQBUPT·2014-07-12 21:00

Principle of Computing (Python)学习笔记(4) Combination + Yahtzee

page=permutations2代码部分http://www.codeskulptor.org/#poc_e
feliciafay·2014-07-11 06:00

[LeetCode]—Permutations II 求全排列（有重复值）

PermutationsII Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample
SUN20082567·2014-07-10 11:00

[LeetCode]—Permutations 求全排列

Permutations Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations
SUN20082567·2014-07-10 10:00

【剑指offer】面试题28：字符串的排列

defPermutation(data,i): iflen(data)==0: return #istandforthestartoffirstpart foriinrange(i,len(data)-
shiquxinkong·2014-07-08 00:00

Check whether array A is a permutation.

TaskdescriptionAnon-emptyzero-indexedarrayAconsistingofNintegersisgiven.Apermutationisasequencecontainingeachelementfrom1toNonce
MagicPocketBiz·2014-07-06 13:23

Check whether array A is a permutation.

TaskdescriptionAnon-emptyzero-indexedarrayAconsistingofNintegersisgiven.Apermutationisasequencecontainingeachelementfrom1toNonce
MagicPocketBiz·2014-07-06 13:23

uva:11129 - An antiarithmetic permutation（分治法）

题目：11129-Anantiarithmeticpermutation题目大意：求n的反算术级数。就是排序0。。n-1要求不存在长度大于2的序列。
u012997373·2014-07-05 21:00

Find the missing element in a given permutation.

TaskdescriptionAzero-indexedarrayAconsistingofNdifferentintegersisgiven.Thearraycontainsintegersintherange[1..(N+1)],whichmeansthatexactlyoneelementismissing.Yourgoalistofindthatmissingelement.Writeaf
MagicPocketBiz·2014-07-02 23:44

[LeetCode]Permutation Sequence

uniquepermutations.Bylistingandlabelingallofthepermutationsinorder,Wegetthefollowingsequence(ie,for n
sbitswc·2014-07-01 06:00

转置-置换-向量空间R

首先是置换（Permutation），前面的A=LU分解中消元都是假设没有行交换，但是有时为了防止主元为0，行交换总是不可避免的，所以如果存在行交换，那么上一篇中的A=LU就变成了PA=LU（A是可逆阵
xdfyoga1·2014-06-30 17:00

Permutations II

做LeetCode44.Permutations时，考虑的就是找出所有uniquepermutations，而且44中也没有考察duplicate的sample,所以同一份代码都能AC思路是num排升序
u014674776·2014-06-29 04:00

Permutations

num排升序，将其加入返回值ret中，再迭代去找它的LeetCode30.NextPermutation代码：classSolution { public: vector>permute(vector&
u014674776·2014-06-29 04:00

[leetcode] Permutation Sequence

uniquepermutations.Bylistingandlabelingallofthepermutationsinorder,Wegetthefollowingsequence(ie,forn=
jdflyfly·2014-06-26 16:00

[leetcode] Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2
jdflyfly·2014-06-26 10:00

[leetcode] Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations
jdflyfly·2014-06-26 10:00

每日算法之三十六：Permutations && Permutations II

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations
yapian8·2014-06-25 20:00

[leetcode] Next Permutation

Implementnextpermutation,whichrearrangesnumbersintothelexicographicallynextgreaterpermutationofnumbers.Ifsucharrangementisnotpossible
jdflyfly·2014-06-25 18:00

全排列

//一种递归实现voidPermutation(char*pStr,char*pBegin) { if(*pBegin=='\0') puts(pStr); else { for(char*pCh=pBegin
bcypxl·2014-06-24 21:00

LeetCode: Permutations

思路：经典题目，A[1,...,k]全排列的生成过程就是先将A[1]与后面的元素一一交换，与剩下的子数组所有的全排列组合起来，得到新的全排列，就比方P1,P2,...是2-k子数组的全排列，那么:A1P1A1P2....是一组，交换A1与A2，得到新的一组排列：A2P^1A2P^2...code:classSolution{ public: voidsolvePermute(vector&num,
AIvin24·2014-06-23 21:00

LeetCode: Next Permutation

思路：1)从数组尾部开始，找一个递增序列，直到出现A[k]::iteratorbegin,vector::iteratorend){ while(begin&A){ intlen=A.size(),index=-1; for(inti=len-1;i>=1;i--) if(A[i-1]A[index]&&A[i]-A[index]<=minV){//注意等于号不要丢到 minV=A[i]-A[in
AIvin24·2014-06-22 11:00

Next Permutation

为找到次大的数，我们尽量保证高位不变，即从十位数起，每次迭代只考察一个数位上的数：假设现为第i次迭代，num[i]，那么从最低位起，考察它右边的的那些数位j；若第j位的数num[j]大于num[i],交换他们，然后将低于i的那些位数排升序--sort(num.begin()+i+1,num.end()),结束程序。代码：classSolution { public: voidnextPermuta
u014674776·2014-06-21 02:00

数据结构与算法[LeetCode]—Permutation Sequence 求n个数的全排列中第K个序列

PermutationSequence Theset [1,2,3,…,n] containsatotalof n!
SUN20082567·2014-06-18 14:00

oral_quiz->#皇后问题#

#include #include voidSwap(int*p1,int*p2){ inttemp=*p1; *p1=*p2; *p2=temp; } voidPermutation(int*ColumnIndex
貉子·2014-06-18 09:00

oral_quiz->#字符串的排列、组合#

///////////////////////////Permutation/////////////////////////////// #include #include voidSwap(char
貉子·2014-06-17 17:00

[LeetCode]—Next Permutation (全排列字典序)

NextPermutationImplementnextpermutation,whichrearrangesnumbersintothelexicographicallynextgreaterpermutationofnumbers.Ifsucharrangementisnotpossible
SUN20082567·2014-06-16 16:00

[leetcode]Permutation Sequence

算法还是一样的算法，但是新博文的代码更简洁，可读性更好，新博文地址：[leetcode]Permutation Sequence Permutation Sequence The set [1,2,3
huntfor·2014-06-16 15:00

[leetcode]Permutation Sequence @ Python

unique permutations. By listing and labeling all of the permutations in order,
·2014-06-13 11:00

[LeetCode68]Permutations Sequence

uniquepermutations.Bylistingandlabelingallofthepermutationsinorder,Wegetthefollowingsequence(ie,for n
sbitswc·2014-06-13 10:00

[LeetCode47]Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2
sbitswc·2014-06-13 06:00

[LeetCode69]Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations
sbitswc·2014-06-13 06:00

[LeetCode31]Next Permutation

Implementnextpermutation,whichrearrangesnumbersintothelexicographicallynextgreaterpermutationofnumbers.Ifsucharrangementisnotpossible
sbitswc·2014-06-13 03:00

[leetcode]Permutations II

新博文地址： [leetcode]PermutationsII Permutations II Given a collection of numbers that might contain duplicates
huntfor·2014-06-12 17:00

[leetcode]Next Permutation

怎么说呢，这篇博文的算法还是很不错的，新博文采用的还是这篇博文的就算法，只不过代码更简洁，可能读可能更好一点，有兴趣请移步，新博文地址：[leetcode]Next Permutation Next
huntfor·2014-06-12 16:00

[LeetCode]Next Permutation

题目描述Implementnextpermutation,whichrearrangesnumbersintothelexicographicallynextgreaterpermutationofnumbers.Ifsucharrangementisnotpossible
cjllife·2014-06-12 15:00

LeetCode Permutation Sequence

uniquepermutations.Bylistingandlabelingallofthepermutationsinorder,Wegetthefollowingsequence(ie,forn=
star_liux·2014-06-11 21:00

[LeetCode]Permutations II

题目描述Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample
cjllife·2014-06-11 17:00
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