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Subarray
LeetCode 974. 和可被 K 整除的子数组 | Python
974.和可被K整除的子数组题目来源:力扣(LeetCode)https://leetcode-cn.com/problems/
subarray
-sums-divisible-by-k题目给定一个整数数组
"大梦三千秋
·
2020-05-27 21:13
LeetCode
和可被
K
整除的子数组
python
算法
前缀和
leetcode
LeetCode每日一题5月27日 LeetCode974. 可被K整除的子数组
来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/
subarray
-sums-divisible-by-k示例:输入:A=[4,5,0,-2,-3,1
青日五月
·
2020-05-27 10:47
LeetCode刷题记录
leetcode
算法
数据结构
【LeetCode】152.乘积最大子数组
题目链接https://leetcode-cn.com/problems/maximum-product-
subarray
/题目描述给你一个整数数组nums,请你找出数组中乘积最大的连续子数组(该子数组中至少包含一个数字
控球强迫症
·
2020-05-18 22:00
【LeetCode】560. 和为K的子数组(前缀和+哈希表)
题目链接https://leetcode-cn.com/problems/
subarray
-sum-equals-k/题目描述给定一个整数数组和一个整数k,你需要找到该数组中和为k的连续的子数组的个数。
控球强迫症
·
2020-05-16 12:00
【每日一题】LeetCode. 560. 和为k的子数组
来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/
subarray
-sum-equals-k二、题目思路以及AC代码我一开始一看这道题,就把DP和暴力的想法给否定了
顺其灬自然丨
·
2020-05-15 10:36
每日一题
leetcode
数据结构
算法
哈希表
LeetCode每日一题5月15日 LeetCode560,和为k的子数组
来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/
subarray
-sum-equals-k示例1:输入:nums=[1,1,1],k=2输出:2,[
青日五月
·
2020-05-15 09:35
LeetCode刷题记录
leetcode
算法
数据结构
【LeetCode】23.最大子序和
题目链接https://leetcode-cn.com/problems/maximum-
subarray
/题目描述给定一个整数数组nums,找到一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和
控球强迫症
·
2020-05-03 12:00
Continuous
Subarray
Sum
题目Givenalistofnon-negativenumbersandatargetintegerk,writeafunctiontocheckifthearrayhasacontinuoussubarrayofsizeatleast2thatsumsuptothemultipleofk,thatis,sumsupton*kwherenisalsoaninteger.Example1:Input
BLUE_fdf9
·
2020-04-14 05:42
Maximum
Subarray
Findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestsum.Forexample,giventhearray[-2,1,-3,4,-1,2,1,-5,4],thecontiguoussubarray[4,-1,2,1]hasthelargestsum=6.Morepractice:I
咿呀咿呀呦__
·
2020-04-12 17:26
使用Javascript做算法题(一)Maximum
Subarray
前言最近开始在leetcode上接触算法题,印象中的算法题大都是用cpp或者java解的,而这个网站支持javascript解题提交。因为大学也没学过算法,数据结构也只是稍微了解,所以解题目标也是选简单经典的题。下面开始讲解这道题--53.MaximumSubarray.题目地址题目描述给出一个由数字组成(含负数)的数组,找出它的一个每项相加之和最大的子数组,返回这个最大和数字。举例:给出一个数组
ITgecko
·
2020-04-12 07:44
Continuous
Subarray
Sum
题目Givenalistofnon-negativenumbersandatargetintegerk,writeafunctiontocheckifthearrayhasacontinuoussubarrayofsizeatleast2thatsumsuptothemultipleofk,thatis,sumsupton*kwherenisalsoaninteger.Example1:Input
yxwithu
·
2020-04-12 06:55
Leetcode - Maximum Size
Subarray
Sum Equals k
Mycode:publicclassSolution{publicintmaxSubArrayLen(int[]nums,intk){if(nums==null||nums.length==0)return0;intmax=0;HashMaptracker=newHashMap();intsum=0;tracker.put(0,-1);for(inti=0;imap=newHashMap();ma
Richardo92
·
2020-04-12 04:10
Minimum Size
Subarray
Sum
Givenanarrayofnpositiveintegersandapositiveintegers,findtheminimallengthofacontiguoussubarrayofwhichthesum≥s.Ifthereisn'tone,return0instead.Forexample,giventhearray[2,3,1,2,4,3]ands=7,thesubarray[4,3]
弓三水
·
2020-04-11 03:57
Maximum
Subarray
Findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestsum.Forexample,giventhearray[-2,1,-3,4,-1,2,1,-5,4],thecontiguoussubarray[4,-1,2,1]hasthelargestsum=6.Consideration:
a_void
·
2020-04-10 23:18
Sum of
Subarray
Minimums
思路:A[i]是最低值的次数=(左边连续的大于A[i]的个数+1)*(右边连续大于等于A[i]的个数+1)classSolution{public:intsumSubarrayMins(vector&A){longlongsum=0;intn=A.size();vectorl(n,-1),r(n,n),st;for(inti=0;iA[i])st.pop_back();l[i]=st.empty(
想学会飞行的阿番
·
2020-04-10 18:21
Maximum
Subarray
. [easy]
链接:MaximumSubarray题意:给定一串字符串a[1...n],找出一个字串a[i...j](0#include#includeusingnamespacestd;intmaxSubArray(vector&nums){intmaxSum=nums[0],tSum=0;for(inti=0;inums;intn,x;cin>>n;for(inti=0;i>x;nums.push_back
大力士_f398
·
2020-04-09 22:24
Maximum Product
Subarray
publicclassSolution{publicintmaxProduct(int[]nums){if(nums.length==0)return0;intmin=nums[0],max=nums[0],res=nums[0];for(inti=1;i
夜皇雪
·
2020-04-09 17:55
209 Minimum Size
Subarray
Sum
这道题给定了我们一个数字,让我们求子数组之和大于等于给定值的最小长度。先来看O(n)的解法:我们需要定义两个指针left和right,分别记录子数组的左右的边界位置,初始都指向array[0],然后我们让right向右移(子序列扩大),直到子数组和大于等于给定值或者right达到数组末尾,此时我们更新最短距离。然后看看能不能得到更小的符合条件的子序列,将left像右移一位进行尝试,如果还是大于,继
yangqi916
·
2020-04-09 00:20
Maximum Product
Subarray
Findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestproduct.Forexample,giventhearray[2,3,-2,4],thecontiguoussubarray[2,3]hasthelargestproduct=6.publicclassSolution{publ
HalcyonMoon
·
2020-04-07 16:06
Maximum Product
Subarray
152.MaximumProductSubarrayGivenanintegerarraynums,findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestproduct.Example1:Input:[2,3,-2,4]Output:6Explanation:[2,3]hasthela
随时学丫
·
2020-04-07 15:22
Maximum
Subarray
Findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestsum.Forexample,giventhearray[-2,1,-3,4,-1,2,1,-5,4],thecontiguoussubarray[4,-1,2,1]hasthelargestsum=6.一刷题解:初始设置结果为In
Jeanz
·
2020-04-06 22:18
Maximum
Subarray
题目53.MaximumSubarrayFindthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestsum.Forexample,giventhearray[-2,1,-3,4,-1,2,1,-5,4],thecontiguoussubarray[4,-1,2,1]hasthelargest
evil_ice
·
2020-04-06 21:54
CF513E2
Subarray
Cuts
Link在\(s\)序列中,极大值对答案的贡献系数为\(2\),极小值的贡献系数为\(-2\),中间部分为\(0\)。(若为首尾,则系数为\(\pm1\))。设\(f_{i,j,k}\)表示前\(i\)个数,分成\(j\)段,此时状态为\(k\)的答案。总共有四种状态:极大值、极大值到极小值、极小值、极小值到极大值。转移非常显然,注意要对首尾进行特判。#include#include#includ
Shiina_Mashiro
·
2020-04-06 18:00
Shortest Unsorted Continuous
Subarray
[2,6,4,8,10,9,15]max记录当前数字之前的最大值比如4之前的[2,6]是6,一直找到最后一个满足以上条件的坐标,标记为endmin记录当前数字之后的最小值,比如10之后的[9,15]最小值是9,当前值如果比max小,暂定为破坏递增排序数组的最后一个数字end[2,6,4,8,10,9,15]就是4->9当前值如果大于min,暂定为浦破坏递增的第一个数start10->6所以star
larrymusk
·
2020-04-06 18:15
674. Longest Continuous Increasing Subsequence
DescriptionGivenanunsortedarrayofintegers,findthelengthoflongestcontinuousincreasingsubsequence(
subarray
Nancyberry
·
2020-04-05 17:13
Leetcode - Maximum Product
Subarray
Paste_Image.pngMycode:publicclassSolution{publicintmaxProduct(int[]nums){if(nums==null||nums.length==0)return0;elseif(nums.length==1)returnnums[0];intmax=nums[0];intcurrMax=nums[0];intcurrMin=nums[0];
Richardo92
·
2020-04-05 13:16
Maximum
Subarray
Findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestsum.Forexample,giventhearray[-2,1,-3,4,-1,2,1,-5,4],thecontiguoussubarray[4,-1,2,1]hasthelargestsum=6.题意:找到最大公共数组目前时
关玮琳linSir
·
2020-04-04 09:27
Continuous
Subarray
Sum
Givenalistofnon-negativenumbersandatargetintegerk,writeafunctiontocheckifthearrayhasacontinuoussubarrayofsizeatleast2thatsumsuptothemultipleofk,thatis,sumsupton*kwherenisalsoaninteger.Example1:Input:[
sherwin29
·
2020-04-04 08:41
Minimum Size
Subarray
Sum
最短子数组之和。题意是给一个数组和一个数字S。请找出一个最短的子数组满足子数组里面数字之和大于等于S。例子,Example:Input:s=7,nums=[2,3,1,2,4,3]Output:2Explanation:thesubarray[4,3]hastheminimallengthundertheproblemconstraint.还是slidingwindow的思路做。给两个指针left
朝鲜冷面杀手
·
2020-04-03 15:00
Maximum Size
Subarray
Sum <= k
给定一个无序数组arr,其中元素可正,可负,可0,给定一个整数k.求arr所有的子数组中累加和小于或等于k的最长子数组长度.例如:arr[]={3,-2,-4,0,6},k=2相加和小于或等于-2的最长子数组为[3,-2,-4,0],所有结果返回4.算法分析基本思想是,分别求以数组每个元素结尾的子数组中,累加和小于或等于k的最长子数组长度,其中最长的那个子数组的长度就是所求的结果.关键是如何高效地
周肃
·
2020-04-01 03:35
Lintcode138
Subarray
Sum solution 题解
【题目描述】Givenanintegerarray,findasubarraywherethesumofnumbersiszero.Yourcodeshouldreturntheindexofthefirstnumberandtheindexofthelastnumber.Notice:Thereisatleastonesubarraythatit'ssumequalstozero.给定一个整数数
程风破浪会有时
·
2020-03-31 18:59
LintCode_chapter2_section2_
subarray
-sum
coding=utf-8'''Createdon2015年11月6日@author:SphinxW'''#子数组之和##给定一个整数数组,找到和为零的子数组。你的代码应该返回满足要求的子数组的起始位置和结束位置#样例##给出[-3,1,2,-3,4],返回[0,2]或者[1,3].classSolution:"""@paramnums:Alistofintegers@return:Alistofi
穆弋
·
2020-03-31 01:09
Subarray
Products No larger than k
Paste_Image.pngpackagesubArrays;importstaticorg.junit.Assert.assertEquals;publicclassProductSubarray{/**Wedefineasubarrayofanarray,numbers,*tobeacontiguousblockofnumbers'elementshavingalength*thatisle
Zihowe
·
2020-03-31 01:42
Continuous
Subarray
Sum
题目链接Givenalistofnon-negativenumbersandatargetintegerk,writeafunctiontocheckifthearrayhasacontinuoussubarrayofsizeatleast2thatsumsuptothemultipleofk,thatis,sumsupton*kwherenisalsoaninteger.Example1:Inp
DrunkPian0
·
2020-03-29 17:01
Maximum
Subarray
典型动态规划问题Findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestsum.Forexample,giventhearray[-2,1,-3,4,-1,2,1,-5,4],thecontiguoussubarray[4,-1,2,1]hasthelargestsum=6.思路非常简单
lmem
·
2020-03-29 13:35
Continuous
Subarray
Sum(连续子数组求和)
http://www.lintcode.com/zh-cn/problem/continuous-
subarray
-sum/?
天街孤独
·
2020-03-29 08:40
Maximum
Subarray
Difference(最大子数组差)
http://www.lintcode.com/zh-cn/problem/maximum-
subarray
-difference/publicclassSolution{/**@paramnums:Alistofintegers
天街孤独
·
2020-03-29 07:32
算法原型——子数组最大和(Array DP)
题目描述求一个数组的子数组最大和例如[3,-2,1,6,-9,1,2,3]那么这个数组的子数组最大和为8[3,-2,1,6][leetcode53]https://leetcode.com/problems/maximum-
subarray
futurehau
·
2020-03-29 00:58
Leetcode_53 Maximum
Subarray
给定一个整数数组,找到一个具有最大和的连续子数组(子数组最少包含一个数),返回其最大和。例如,给定数组[-2,1,-3,4,-1,2,1,-5,4],连续子数组[4,-1,2,1]的和最大,为6。"""遍历数组,当从头到尾部遍历数组遇到一个数有两种选择:keypoint:(1)加上这个数后数值变大:继续加后面的数,最大值为当前相加后的值(2)加上这个数后数值变小:从当前开始重新加后面的数,最大值为
vcancy
·
2020-03-25 15:00
Shortest Unsorted Continuous
Subarray
题目描述Givenanintegerarray,youneedtofindonecontinuoussubarraythatifyouonlysortthissubarrayinascendingorder,thenthewholearraywillbesortedinascendingorder,too.Youneedtofindtheshortestsuchsubarrayandoutputi
龙之力量V
·
2020-03-25 04:31
乘积最大子序列(Maximum Product
Subarray
)
image.png152.乘积最大子序列乘积最大子序列给定一个整数数组nums,找出一个序列中乘积最大的连续子序列(该序列至少包含一个数)。示例1:输入:[2,3,-2,4]输出:6解释:子数组[2,3]有最大乘积6。示例2:输入:[-2,0,-1]输出:0解释:结果不能为2,因为[-2,-1]不是子数组。Python3实现暴力求解#@author:leacoder#@des:暴力求解乘积最大子序
leacoder
·
2020-03-24 15:59
Maximum
Subarray
题目分析Findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestsum.Forexample,giventhearray[-2,1,-3,4,-1,2,1,-5,4],thecontiguoussubarray[4,-1,2,1]hasthelargestsum=6.代码一动态规划的思想
衣介书生
·
2020-03-23 23:54
Maximum Product
Subarray
publicclassSolution{publicintmaxProduct(int[]nums){if(nums==null||nums.length==0)return0;intmax_prev=nums[0];intmin_prev=nums[0];intmax_so_far=nums[0];intmax_curr,min_curr;for(inti=1;i
沉睡至夏
·
2020-03-23 09:52
Maximum Product
Subarray
一、题目说明题目152.MaximumProductSubarray,给一列整数,求最大连续子序列,其乘积最大。难度是Medium!二、我的解答这个题目,用双重循环就可以了。classSolution{public:intmaxProduct(vector&nums){if(nums.size()product)product=p;for(intt=i+1;tproduct)product=p;}
siwei718
·
2020-03-22 08:00
亚麻Arithmetic Sequence系列
ArithmeticSequenceIBruteForce:暴力解法也是很重要的两层Loop的关键一个是start,一个是end.其实这个暴力解法都挺优秀了,不是那么好想到的这题是一个经典的DP题,用DP[i]表示
subarray
0
98Future
·
2020-03-22 04:02
Leetcode - Maximum
Subarray
Mycode:publicclassSolution{publicintmaxSubArray(int[]nums){if(nums==null||nums.length==0)return0;elseif(nums.length==1)returnnums[0];intmaxSum=nums[0];intcurrSum=nums[0];for(inti=1;i=0?currSum+nums[i]
Richardo92
·
2020-03-21 21:13
Minimum Size
Subarray
Sum
问题描述Givenanarrayofnpositiveintegersandapositiveintegers,findtheminimallengthofasubarrayofwhichthesum≥s.Ifthereisn'tone,return0instead.Forexample,giventhearray[2,3,1,2,4,3]ands=7,thesubarray[4,3]hasthe
codingXue
·
2020-03-21 18:39
DP_Maximum product
Subarray
一、题目Findthecontiguoussubarraywithinanarray(containingatleastonenumber)whichhasthelargestproduct.Forexample,giventhearray[2,3,-2,4],thecontiguoussubarray[2,3]hasthelargestproduct=6.在一个数组中,寻找一个连续子数组使得成绩
Arthur_7724
·
2020-03-21 13:17
Sum of
Subarray
Minimums
思路实际上是要求res=sum(A[i]*f(i)),其中f(i)是子数组的数量,A[i]是最小值。为了得到f(i),我们要得到left[i],能在A[i]左侧取得的最长宽度,使得在这个范围内A[i]是最小值,且都大于A[i]right[i],能在A[i]右侧取得的最长宽度,使得在这个范围内A[i]是最小值,且都大于等于A[i]然后,A[i]左侧有left[i]+1种连续子数组的取法A[i]右侧有
不存在的里皮
·
2020-03-18 10:07
Maximum Average
Subarray
I
题目Givenanarrayconsistingofnintegers,findthecontiguoussubarrayofgivenlengthkthathasthemaximumaveragevalue.Andyouneedtooutputthemaximumaveragevalue.Example1:Input:[1,12,-5,-6,50,3],k=4Output:12.75Explan
miltonsun
·
2020-03-16 12:44
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