HDOJ 1012 u Calculate e（水题）

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 35342    Accepted Submission(s): 15934

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

   
   
   
   

    
    
    
    n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
   
   
   
   

 

ac代码：

#include<stdio.h>
int main()
{
    double sum,s=1;
    int i;
    printf("n e\n");
    printf("- -----------\n");
    sum=1;
    printf("0 1\n");
    for(i=1;i<=9;i++)
    {
        s=s*i;
        sum+=1/s;
        if(i==1)
        printf("%d %d\n",i,(int)sum);
        if(i==2)
        printf("%d %.1lf\n",i,sum);
        if(i>2)
        printf("%d %.9lf\n",i,sum);
    }
    return 0;
}