查看 Oracle 位数的方法
1、使用sqlplus命令
[rac11g1@oracle]$ sqlplus / as sysdba
SQL*Plus: Release 11.2.0.2.0 Production on Wed Feb 15 16:19:43 2012
Copyright (c) 1982, 2010, Oracle. All rights reserved.
Connected to:
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bitProduction
With the Partitioning, Real Application Clusters, Automatic Storage Management, OLAP,
Data Mining and Real Application Testing options
如果是64位，用sqlplus 连上之后会显示具体的位数信息，32位则不会显示。
[oracle@srccat ~]$ sqlplus / as sysdba
SQL*Plus: Release 10.2.0.4.0 - Production on Wed Feb 15 16:11:47 2012
Copyright (c) 1982, 2007, Oracle. All Rights Reserved.
Connected to:
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
16:19:43 nint1@SYS>
2、查看v$version视图
16:21:30 nint1@SYS> select * from v$version;
BANNER
----------------------------------------------------------------------------------------------------------------------------------------------------------------
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bitProduction
PL/SQL Release 11.2.0.2.0 - Production
CORE 11.2.0.2.0 Production
TNS for IBM/AIX RISC System/6000: Version 11.2.0.2.0 - Production
NLSRTL Version 11.2.0.2.0 - Production
64位会显示具体的位数信息，同样的32位不会显示
16:11:47 srcbtest@SYS> select * from v$version;
BANNER
----------------------------------------------------------------
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Prod
PL/SQL Release 10.2.0.4.0 - Production
CORE 10.2.0.4.0 Production
TNS for Linux: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
3、查看v$sql视图中的address
64位：输出为16位16进制数
16:21:38 nint1@SYS> select address from v$sql where rownum <2;
ADDRESS
----------------
07000005EFA5EEE8
32位：输出为8位16进制数
16:13:23 srcbtest@SYS> select address from v$sql where rownum <2;
ADDRESS
--------
9FE49FAC