Palindrome Partitioning

Palindrome Partitioning

Given a string s, partition s such that every substring of the partition is a palindrome.

Return all possible palindrome partitioning of s.

For example, given s = "aab",
Return

  [
    ["aa","b"],
    ["a","a","b"]
  ]

深搜

class Solution {
public:
    vector<vector<string>> partition(string s) {
        vector<vector<string>> ret;
        if(s.empty()) return ret;
        
        vector<string> path;
        dfs(0, s, path, ret);
        
        return ret;
    }
    
    void dfs(int index, string &s, vector<string> &path, vector<vector<string>> & ret) {
        if (index == s.size()) {
            ret.push_back(path);
        }
        
        for(int i = index; i < s.size(); ++i) {
            if (isPalindrome(s, index, i)) {
                path.push_back(s.substr(index, i-index+1));
                dfs(i+1, s, path, ret);
                path.pop_back();
            }
        }
    }
    
    bool isPalindrome(const string &s, int start, int end) {
        while(start <= end) {
            if(s[start++] != s[end--])
                return false;
        }
        return true;
    }
    
};