hdoj 2052 Picture

Picture

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 24258    Accepted Submission(s): 12334

Problem Description

Give you the width and height of the rectangle,darw it.

 

Input

Input contains a number of test cases.For each case ,there are two numbers n and m (0 < n,m < 75)indicate the width and height of the rectangle.Iuput ends of EOF.

 

Output

For each case,you should draw a rectangle with the width and height giving in the input.
after each case, you should a blank line.

 

Sample Input

   
   
   
   

    
    
    
    3 2
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    +---+
|   |
|   |
+---+
   
   
   
   

 

Author

xhd

 

Source

校庆杯Warm Up

 

代码：

#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
int a[1010][1010];
int main()
{
    int n,m;
    while(~scanf("%d%d",&n,&m))//几个循环没有没有套路可言
    {
        memset(a,0,sizeof(a));
        a[0][0]=1;
        a[0][n+1]=1;
        a[m+1][0]=1;
        a[m+1][n+1]=1;
        for(int i=1;i<=n;i++)
        {
             a[0][i]=2;
             a[m+1][i]=2;
        }
        for(int j=1;j<=m;j++)
        {
            a[j][0]=3;
            a[j][n+1]=3;
        }
        for(int i=0;i<=m+1;i++)
        {
            for(int j=0;j<=n+1;j++)
            {
                if(a[i][j]==1)
                    printf("+");
                else if(a[i][j]==2)
                    printf("-");
                else if(a[i][j]==3)
                    printf("|");
                else
                    printf(" ");
            }
            printf("\n");
        }
        printf("\n");
    }
    return 0;
}