Bitset（位组）

time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 15281    Accepted Submission(s): 11595

Problem Description

Give you a number on base ten,you should output it on base two.(0 < n < 1000)

 

Input

For each case there is a postive number n on base ten, end of file.

 

Output

For each case output a number on base two.

 

Sample Input

   
   
   
   

    
    
    
    1
2
3
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    1
10
11
   
   
   
   
   
   
   
   

    
    
    
     #include<stdio.h>
void f(int n)
{

    
    
    
     if(n/2) f(n/2);

    
    
    
     printf("%d",n%2);

    
    
    
     
}
 main()
{

    
    
    
     int n;

    
    
    
     while(scanf("%d",&n)!=EOF)
{
    
    
    
     f(n);

    
    
    
     printf("\n");}

    
    
    
     return 0;
}