Palindrom Numbers 任意进制数转换

Palindrom Numbers Time Limit: 2 Seconds       Memory Limit: 65536 KB Statement of the Problem

We say that a number is a palindrom if it is the sane when read from left to right or from right to left. For example, the number 75457 is a palindrom.

Of course, the property depends on the basis in which is number is represented. The number 17 is not a palindrom in base 10, but its representation in base 2 (10001) is a palindrom.

The objective of this problem is to verify if a set of given numbers are palindroms in any basis from 2 to 16.

Input Format

Several integer numbers comprise the input. Each number 0 < n < 50000 is given in decimal basis in a separate line. The input ends with a zero.

Output Format

Your program must print the message Number i is palindrom in basis where I is the given number, followed by the basis where the representation of the number is a palindrom. If the number is not a palindrom in any basis between 2 and 16, your program must print the message Number i is not palindrom.

Sample Input

17
19
0

Sample Output

Number 17 is palindrom in basis 2 4 16
Number 19 is not a palindrom

#include <iostream>   
#include <cstring> 
#include<cmath>
using namespace std; 
short int b[50000],d[50000],r[50000];
int main()
{   
		int a;
        while(cin>>a&&a) 
		{
			int i,m,c,p=0;
			memset(r,0,sizeof(r));
			for(i=2;i<=16;++i)
			{
				memset(b,0,sizeof(b));
				m=a;
				c=0;
				while(m)
				{
					b[c++]=m%i;
					m=m/i;
				}
				int j,k=0;
				for(j=c-1;j>=0;--j)
				{
					d[k++]=b[j];
				}
				for(j=0;j<c;++j)
				{
					if(b[j]!=d[j])
						break;
				}
				
				
				if(j==c)
					r[p++]=i;
			}
			if(p==0)
				cout<<"Number "<<a<<" is not a palindrom"<<endl;
			else
				{
					cout<<"Number "<<a<<" is palindrom in basis ";
					for(int j=0;j<p;j++)
						{
							cout<<r[j];
							if(j==p-1)
								cout<<endl;
							else
								cout<<" ";
					}
			}

		}
      
    return 0;   
}