leetcode 16: 3 Sum closest (C#版)

Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

    For example, given array S = {-1 2 1 -4}, and target = 1.

    The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace _3Sum
{
    class threesumclosest
    {
        public int ThreeSumClosest(int[] nums, int target)
        {
            List<int> myL = nums.ToList();
            myL.Sort();
            int[] mynum = myL.ToArray();
            int start, end, current;
            List<int> mylist = new List<int>();
            List<int> myres = new List<int>();
            for (int i = 0; i < mynum.Length; i++)
            {
                if (i != 0 && mynum[i] == mynum[i - 1])
                {
                    continue;
                }
                start = i + 1;
                end = mynum.Length - 1;
                while (start < end)
                {
                    if (start != i + 1 && mynum[start] == mynum[start - 1])
                    {
                        start++;
                        continue;
                    }
                    current = mynum[i] + mynum[start] + mynum[end];
                    if (target > current)
                    {
                        mylist.Add(target - current);
                        start++;
                    }
                    else
                    {
                        myres.Add(current - target); end--;
                    }
                   
                }

            }
            int x1, x2;
            if (mylist.Count != 0)
            {
                x1 = mylist.Min();
            }
            else
            {
                x1 = myres.Min()+1;
            }
            if (myres.Count != 0)
            {
                x2 = myres.Min();
            }
            else
            {
                x2 = mylist.Min()+1;
            }

            int x3 = target-x1;
            int x4 = target + x2;
            if (mylist == null ||x1> x2)
            {
                return x4;
            }
            else if (myres == null || x1 < x2)
            {
                return x3;
            }
            else
            {
                return x4;
            }
            
        }
    }
}
<pre name="code" class="html">



 

你可能感兴趣的:(LeetCode,.net,算法,C#)