一个String对象是一个unicode字符序列.在C和C++中,string仅仅是一个字符数组(标准C++定义了string类),Java的String是核心包java.lang中的一个对象类。
与普通class不同之处表现在:
String类中的常用方法:
// Length int length() // returns the length of the String boolean isEmpty() // same as thisString.length == 0 // Comparison boolean equals(String another) // CANNOT use '==' or '!=' to compare two Strings boolean equalsIgnoreCase(String another) int compareTo(String another) // return 0 if this string is the same as another; // <0 if lexicographically less than another; or >0 int compareToIgnoreCase(String another) boolean startsWith(String another) boolean startsWith(String another, int fromIndex) // search begins at fromIndex boolean endsWith(String another) // Searching & Indexing int indexOf(String search) int indexOf(String search, int fromIndex) int indexOf(int character) int indexOf(int character, int fromIndex) // search forward starting at fromIndex int lastIndexOf(String search) int lastIndexOf(String search, int fromIndex) // search backward starting at fromIndex int lastIndexOf(int character) int lastIndexOf(int character, int fromIndex) // Extracting character or part of the String char charAt(int index) // index from 0 to String's length - 1 String substring(int fromIndex) String substring(int fromIndex, int endIndex) // exclude endIndex // Creating a new String or char[] from the original (Strings are immutable!) String toLowerCase() String toUpperCase() String trim() // create a new String removing white spaces from front and back String replace(char oldChar, char newChar) // create a new String with oldChar replaced by newChar String concat(String another) // same as thisString + another char[] toCharArray() // create a char[] from this string void getChars(int srcBegin, int srcEnd, char[] dst, int dstBegin) // copy into dst char[] // Static methods for converting primitives to String static String ValueOf(type arg) // type can be primitives or char[] // Static method resulted in a formatted String using format specifiers static String format(String formattingString, Object... args) // same as printf() // Regular Expression (JDK 1.4) boolean matches(String regexe) String replaceAll(String regexe, String replacement) String replaceAll(String regexe, String replacement) String[] split(String regexe) // Split the String using regexe as delimiter, // return a String array String[] split(String regexe, int count) // for count times only
String确实很特殊
在Java中,String享受到了“特殊待遇”,因为它的使用实在是太频繁。因此,效率(而不是计算和存储)是至关重要的。
为了提高Java的性能,Java的设计者们保留了在。这样一种面向对象语言中保留了基本数据类型。
基本数据保存在栈中,占用的空间资源少而且操作效率高;而对象保存在程序堆中,需要进行复杂的内存管理,且需要的空间资源更多。
考虑到性能问题,Java的String被设计成介乎基本数据类型与类类型之间。其特殊性体现在:
String str1 = "Java is Hot"; // Implicit construction via string literal String str2 = new String("I'm cool"); // Explicit construction via new
第一行代码中,str1被声明为一个String引用并通过一个字符串“Java is Hot”来进行初始化;在第二句代码中,str2被声明为一个String引用并通过new操作创建一个内容为“I'm cool”的对象进行初始化。
字符串存储在常量池中。这有便于内容相同的字符串的存储,以节省空间。通过new操作符创建的String对象存储在堆中,且不存在共享机制。
正如所提到的,存在两种方式创建String对象:通过“ ”隐式创建或者通过new操作符显示创建。例如:
String s1 = "Hello"; // String literal String s2 = "Hello"; // String literal String s3 = s1; // same reference String s4 = new String("Hello"); // String object String s5 = new String("Hello"); // String object
Java has designed a special mechanism for keeping theString
literals - in a so-calledstring common pool. If twoString
literals have the same contents, they will share the same storage locations inside the common pool. This approach is adopted toconserve storage for frequently-used strings. On the other hands,String
object created via thenew
operator are kept in the heap. EachString
object in the heap has its own storage just like any other object. There is no sharing of storage in heap even if twoString
objects have the same contents.
You can use the method equals()
of theString
class to compare the contents of twoString
s. You can use the relational equality operator'=='
to compare the references (or pointers) of two objects. Study the following codes:
s1 == s1; // true, same pointer s1 == s2; // true, s1 and s1 share storage in common pool s1 == s3; // true, s3 is assigned same pointer as s1 s1.equals(s3); // true, same contents s1 == s4; // false, different pointers s1.equals(s4); // true, same contents s4 == s5; // false, different pointers in heap s4.equals(s5); // true, same contents
Important Notes:
'=='
to compare the references of twoString
objects. This is done to demonstrate the differences betweenString
literals sharing storage in the common pool andString
objects created in the heap. It is alogical error to use(str1 == str2)
in your program forcomparing the contents of twoString
s.String
can be created by directly assigning aString
literal which is shared in a common pool. It is uncommon and not recommended to use the new operator to construct aString
object in the heap. [TODO] Explain the method String.intern()
.
Since String
literals with the same contents share storage in the common pool, Java'sString
isimmutable. That is, once aString
is constructed, its contents cannot be modified. Otherwise, the otherString
references sharing the same storage location will be affected by the change, which can be unpredictable and therefore is undesirable. Methods such astoUpperCase()
might appear to modify the contents of aString
object. In fact, a completely newString
object is created and returned to the caller. The originalString
object will be deallocated, once there is no more references, and subsequently garbage-collected.
Because String
is immutable, it is not efficient to useString
if you need to modify your string frequently (that would create many newString
s occupying new storage areas). For example,
// inefficient codes String str = "Hello"; for (int i = 1; i < 1000; i++) { str = str + i; }
If the contents of a String
have to be modified frequently, use theStringBuffer
orStringBuilder
class instead.
As explained earlier, String
s areimmutable becauseString
literals with same content share the same storage in the string common pool. Modifying the content of oneString
directly may cause adverse side-effects to otherString
s sharing the same storage.
JDK provides two classes to support mutable strings: StringBuffer
and StringBuilder
(in core packagejava.lang
) . AStringBuffer
orStringBuilder
object is just like any ordinary object, which are stored in the heap and not shared, and therefore, can be modified without causing adverse side-effect to other objects.
StringBuilder
class was introduced in JDK 1.5. It is the same asStringBuffer
class, except thatStringBuilder
isnot synchronized for multi-thread operations. However, for single-thread program,StringBuilder
, without the synchronization overhead, is more efficient.
Read the JDK API specification for java.lang.StringBuffer
.
// Constructors StringBuffer() // an initially-empty StringBuffer StringBuffer(int size) // with the specified initial size StringBuffer(String s) // with the specified initial content // Length int length() // Methods for building up the content StringBuffer append(type arg) // type could be primitives, char[], String, StringBuffer, etc StringBuffer insert(int offset, arg) // Methods for manipulating the content StringBuffer delete(int start, int end) StringBuffer deleteCharAt(int index) void setLength(int newSize) void setCharAt(int index, char newChar) StringBuffer replace(int start, int end, String s) StringBuffer reverse() // Methods for extracting whole/part of the content char charAt(int index) String substring(int start) String substring(int start, int end) String toString() // Methods for searching int indexOf(String searchKey) int indexOf(String searchKey, int fromIndex) int lastIndexOf(String searchKey) int lastIndexOf(String searchKey, int fromIndex)
Take note that StringBuffer
is an ordinary object. You need to use a constructor to create aStringBuffer
(instead of assigning to a String
literal). Furthermore,'+'
operator does not apply to objects, inclusive of StringBuffer
. You need to use a proper method such asappend()
or insert()
to manipulating a StringBuffer
.
To create a string from parts, It is more efficient to useStringBuffer
(multi-thread) orStringBuilder
(single-thread) instead of viaString
concatenation. For example,
// Create a string of YYYY-MM-DD HH:MM:SS int year = 2010, month = 10, day = 10; int hour = 10, minute = 10, second = 10; String dateStr = new StringBuilder() .append(year).append("-").append(month).append("-").append(day).append(" ") .append(hour).append(":").append(minute).append(":").append(second).toString(); System.out.println(dateStr); // StringBuilder is more efficient than String concatenation String anotherDataStr = year + "-" + month + "-" + day + " " + hour + ":" + minute + ":" + second; System.out.println(anotherDataStr);
JDK compiler, in fact, uses both String
and StringBuffer
to handle string concatenation via the'+'
operator. For examples,
String msg = "a" + "b" + "c";
will be compiled into the following codes for better efficiency:
String msg = new StringBuffer().append("a").append("b").append("c").toString();
Two objects are created during the process, an intermediateStringBuffer
object and the returnedString
object.
Rule of Thumb:String
s are more efficient if they are not modified (because they are shared in the string common pool). However, if you have to modify the content of a string frequently (such as a status message), you should use theStringBuffer
class (or theStringBuilder
described below) instead.
Java SE 5 introduced a new StringBuilder
class (in packagejava.lang
), which is almost identical to theStringBuffer
class, except that it isnot synchronized. In other words, if multiple threads are accessing aStringBuilder
instance at the same time, its integrity cannot be guaranteed. However, for a single-thread program (most commonly), doing away with the overhead of synchronization makes theStringBuilder
slightly faster.
StringBuilder
is API-compatible with theStringBuffer
class, i.e., having the same set of constructors and methods, but with no guarantee of synchronization. It can be a drop-in replacement forStringBuffer
under a single-thread environment.
The following program compare the times taken to reverse a longString
via aString
object an aStringBuffer
.
// Reversing a long String via a String vs. a StringBuffer public class StringBufferTest { public static void main(String[] args) { long beginTime, elapsedTime; // Build a long string String str = ""; int size = 2048; // program hangs for size > 4000?? char c = 'a'; beginTime = System.nanoTime(); // Reference time in nanoseconds for (int count = 0; count < size; count++) { str += c; c++; if (c > 'z') { c = 'a'; } } elapsedTime = System.nanoTime() - beginTime; System.out.println("Elapsed Time is " + elapsedTime/1000 + " us"); // Reverse a String by building another String character-by-character in the reverse order String strReverse = ""; beginTime = System.nanoTime(); for (int pos = str.length() - 1; pos >= 0 ; pos--) { strReverse += str.charAt(pos); // Concatenate } elapsedTime = System.nanoTime() - beginTime; System.out.println("Elapsed Time is " + elapsedTime/1000 + " us"); // Reverse a String via an empty StringBuffer by appending characters in the reverse order beginTime = System.nanoTime(); StringBuffer sb = new StringBuffer(size); for (int pos = str.length() - 1; pos >= 0 ; pos--) { sb.append(str.charAt(pos)); // append } elapsedTime = System.nanoTime() - beginTime; System.out.println("Elapsed Time is " + elapsedTime/1000 + " us"); // Reverse a String by creating a StringBuffer with the given String and invoke its reverse() beginTime = System.nanoTime(); StringBuffer sb1 = new StringBuffer(str); sb1.reverse(); // use reverse() method elapsedTime = System.nanoTime() - beginTime; System.out.println("Elapsed Time is " + elapsedTime/1000 + " us"); } }
Elapsed Time is 17006 us (Building the String)
Elapsed Time is 9370 us (Reversing via building another String character-by-character)
Elapsed Time is 535 us (Reversing via an empty StringBuffer and append character-by-character)
Elapsed Time is 148 us (Reversing via creating a StringBuffer with the given string, then reverse()
Observe that constructing a StringBuffer
and then using thereverse()
method is 4 times faster than building aStringBuffer
character-by-character; and is 60 times faster than using theString
object.
// Comparing StringBuffer and StringBuilder via reversing a long string public class StringBuilderTest { public static void main(String[] args) { long beginTime, elapsedTime; // Build a long string String str = ""; int size = 2048; // program hangs for size > 4000?? char c = 'a'; for (int count = 0; count < size; count++) { str += c; c++; if (c > 'z') { c = 'a'; } } // Reverse a String via an empty StringBuffer by appending characters in the reverse order beginTime = System.nanoTime(); StringBuffer sBuffer1 = new StringBuffer(size); for (int pos = str.length() - 1; pos >= 0 ; pos--) { sBuffer1.append(str.charAt(pos)); } elapsedTime = System.nanoTime() - beginTime; System.out.println("Elapsed Time is " + elapsedTime/1000 + " us"); // Repeat with StringBuilder beginTime = System.nanoTime(); StringBuilder sBuilder1 = new StringBuilder(size); for (int pos = str.length() - 1; pos >= 0 ; pos--) { sBuilder1.append(str.charAt(pos)); } elapsedTime = System.nanoTime() - beginTime; System.out.println("Elapsed Time is " + elapsedTime/1000 + " us"); // Reverse a String by creating a StringBuffer with the given String and invoke its reverse() beginTime = System.nanoTime(); StringBuffer sBuffer2 = new StringBuffer(str); sBuffer2.reverse(); elapsedTime = System.nanoTime() - beginTime; System.out.println("Elapsed Time is " + elapsedTime/1000 + " us"); // Repeat with StringBuilder beginTime = System.nanoTime(); StringBuffer sBuilder2 = new StringBuffer(str); sBuilder2.reverse(); elapsedTime = System.nanoTime() - beginTime; System.out.println("Elapsed Time is " + elapsedTime/1000 + " us"); } }
Elapsed Time is 849 us (StringBuffer)
Elapsed Time is 204 us (StringBuilder)
Elapsed Time is 190 us (StringBuffer)
Elapsed Time is 131 us (StringBuilder)
Observer that StringBuilder
is always faster than theStringBuilder
, although the absolute timing varies from run to run.
Very often, you need to break a line of texts into tokens delimited by white spaces. TheStringTokenizer
class supports this.
For example, the following program reverses the words in a String.
// Reverse the words in a String using StringTokenizer import java.util.StringTokenizer; public class StringTokenizerTest { public static void main(String[] args) { String str = "Monday Tuesday Wednesday Thursday Friday Saturday Sunday"; String strReverse; StringBuilder sb = new StringBuilder(); StringTokenizer st = new StringTokenizer(str); while (st.hasMoreTokens()) { sb.insert(0, st.nextToken()); if (st.hasMoreTokens()) { sb.insert(0, " "); } } strReverse = sb.toString(); System.out.println(strReverse); } } // Constructors StringTokenizer(String s) // Constructs a StringTokenizer for the given string, // using the default delimiter set of " \t\n\r\f" // (i.e., blank, tab, newline, carriage-return, and form-feed). // Delimiter characters themselves will not be treated as tokens. StrintTokenizer(String s, String delimiterSet) // Use characters in delimiterSet as delimiters. // Methods boolean hasNextToken() // Returns true if next token available String nextToken() // Returns the next token // Code Sample StringTokenizer tokenizer = new StringTokenizer(aString); while (tokenizer.hasNextToken()) { String token = tokenizer.nextToken(); ..... }
The JDK documentation stated that "StringTokenizer
is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split()
method of String
or the java.util.regex
package instead."
For example, the following program uses the split() method of the String class to reverse the words of a String.
// Reverse the words in a String using split() method of the String class public class StringSplitTest { public static void main(String[] args) { String str = "Monday Tuesday Wednesday Thursday Friday Saturday Sunday"; String[] tokens = str.split("\\s"); // white space '\s' as delimiter StringBuilder sb = new StringBuilder(); for (int i = 0; i < tokens.length; i++) { sb.insert(0, tokens[i]); if (i < tokens.length - 1) { sb.insert(0, " "); } } String strReverse = sb.toString(); System.out.println(strReverse); } }原文URL:点击打开链接