GET Android 摸拟器 IP.

 

简单做了一个android的project

想能过以下代码取得摸拟器的IP:

public String getLocalIpAddress() 
 { 
     try 
     { 
         for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) 
         { 
            NetworkInterface intf = en.nextElement(); 
            for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) 
            { 
                InetAddress inetAddress = enumIpAddr.nextElement(); 
                if (!inetAddress.isLoopbackAddress()) 
                { 
                    return inetAddress.getHostAddress().toString(); 
                } 
            } 
        } 
     } 
     catch (SocketException ex) 
     { 
         //Log.e(S.TAG, ex.toString()); 
     } 
     return null;
 }

 

运行结果,为NULL,百思不得其解,

尝试方法二:

try {
    Socket socket = new Socket("www.droidnova.com", 80);
    Log.i("", socket.getLocalAddress().toString());
} catch (Exception e) {
    Log.i("", e.getMessage());
}

 

同样无解.晕

万事,还真是开头难.

 

找STORM哥帮手:

修改XML如下:

 

 

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
      package="com.test.main"
      android:versionCode="1"
      android:versionName="1.0">
    <application android:icon="@drawable/icon" android:label="@string/app_name">
        <activity android:name=".hello"
                  android:label="@string/app_name">
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />
                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>

    </application>
    <uses-sdk android:minSdkVersion="8" />

<uses-permission android:name="android.permission.INTERNET"></uses-permission>
</manifest>

 

重点在红色部分.解决,记录