数据库和xml协同工作（3）

1。读取xml文件，并且采用数据绑定控件（datalist、gridview、repeater） 或者 采用 树形控件 显示

前台：

用表显示： < br />

< asp:Label ID ="Label1" runat ="server" Text ="Label" ></ asp:Label >
< asp:GridView ID ="GridView1" runat ="server" >
</ asp:GridView >

< asp:Label ID ="Label2" runat ="server" Text ="Label" ></ asp:Label >
< asp:GridView ID ="GridView2" runat ="server" >
</ asp:GridView >

< asp:Label ID ="Label3" runat ="server" Text ="Label" ></ asp:Label >
< asp:GridView ID ="GridView3" runat ="server" >
</ asp:GridView >
< br />
树形显示 < br />
&nbsp; < asp:Label ID ="Label4" runat ="server" Text ="Label" ></ asp:Label >

2。后台文件

DataSetds = new DataSet();

ds.ReadXml(MapPath( " RecipeList.xml " ));

// 如果以表显示XML，则用DataSet

Label1.Text = ds.Tables[ 0 ].TableName;
GridView1.DataSource = ds.Tables[ 0 ];
GridView1.DataBind();

Label2.Text = ds.Tables[ 1 ].TableName;
GridView2.DataSource = ds.Tables[ 1 ];
GridView2.DataBind();

Label3.Text = ds.Tables[ 2 ].TableName;
GridView3.DataSource = ds.Tables[ 2 ];
GridView3.DataBind();

// 如果用树显示DataSet，则选用xmlDataDocument
XmlDataDocumentxdd = new XmlDataDocument(ds);
XmlNodeListrecipes = xdd.GetElementsByTagName( " Ingredient " );
foreach (XmlNoderecipe in recipes)
... {
Label4.Text+=recipe.InnerText+"<br/>";
}

xml文件

<? xmlversion="1.0"encoding="utf-8" ?>
< RecipeList >
< Recipe >
< Name > FrechToast </ Name >
< Ingredients >
< Ingredient > Bread </ Ingredient >
< Ingredient > Butter </ Ingredient >
< Ingredient > Sugar </ Ingredient >
</ Ingredients >
</ Recipe >
< Recipe >
< Name > TomatoSoup </ Name >
< Ingredients >
< Ingredient > Tomatoes </ Ingredient >
< Ingredient > Water </ Ingredient >
</ Ingredients >
</ Recipe >
</ RecipeList >