JqueryAjax像controller传参数

第一种方法：

function insert(){          
          var val = {"stuNum":4,"name":"stu4","classNum":4};    
             $.ajax({                  
                type:"POST",  
                url:"../test/yn/insert",                   
                dataType: "json",                
                data:val,               
                success: function(student){                    
                    defaultPage();
                }  
                })           
     }

@RequestMapping("insert")
    @ResponseBody
    public Student methodsInsert(int stuNum,String name,int classNum){
        Student student = new Student(stuNum,name,classNum);
        stuService.insertStudent(student);
        System.out.println(name);
        return new Student();
    }