HDU 1076 An Easy Task

题解：枚举即可……

#include <cstdio>

int main(){

    int now,y,n,T,count;

    scanf("%d",&T);

    while(T--){

        scanf("%d%d",&y,&n);

        for(now=y;;now++){

            if((now%4==0&&now%100!=0)||(now%400)==0)n--;

            if(!n){printf("%d\n",now);break;}

         }

    }return 0;

}