编写打印一个单链表所有元素的程序

#include<stdio.h>

#include<stdlib.h>

struct Node;

typedef struct Node *PtrToNode;

typedef PtrToNode List;

typedef PtrToNode Position;



struct Node{

    int  Ele;

    Position Next;

};

void

PrintArray(List L)

{

    Position p;

    p = L;

    while( p->Next != NULL )

    {

        printf("%d",p->Next->Ele);

        p = p->Next;

    }

}

Position

CreateTable( void )

{

    PtrToNode L;

    L = malloc( sizeof( struct Node ) );

    if( L == NULL){

        printf("out of space ");

        return ;

    }

    L->Next = NULL;

    return L;

}



int main()

{



    int i;

    Position L,p;

    PtrToNode TmpCell;

    L = CreateTable();

    p = L;

    for(i = 0; i<3; i++ )

    {

        TmpCell = malloc(sizeof(struct Node ));

        if(TmpCell == NULL)

        {

            printf("error");

            return;

        }

        p->Next = TmpCell;



        TmpCell->Ele = i;

        TmpCell->Next = NULL;



        p = TmpCell;

    }

    PrintArray( L );

}

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 这里面涉及到：for循环做一个链表由下往上做，链表却是由上往下