2019-10-23 SpringBOOT Json数据接收返回格式

问题 传入的日期是字符串类型 json 如下

{"promotename":"促销","starttime":"2019-10-01 00:00:01","endtime":"2019-10-31 23:59:59","rpmax":"1","rpmin":"2"}

页面抽取的日期格式如下：

2019-09-30T16:00:00.000+0000

解决方案：

使用 JsonSerialize与 JsonDeserialize 来处理json转换date日期

添加2个类分别继承 JsonDeserializer和JsonSerializer

public class DateJsonSerializer extends JsonSerializer {public static final SimpleDateFormat format=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); @Override public void serialize(Date date, JsonGenerator jsonGenerator, SerializerProvider serializerProvider) throws IOException { jsonGenerator.writeString(format.format(date)); } } 

---

public class DateJsonDeserializer extends JsonDeserializer { public static final SimpleDateFormat format=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); @Override public Date deserialize(com.fasterxml.jackson.core.JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException, com.fasterxml.jackson.core.JsonProcessingException { try { if(jsonParser!=null&&StringUtils.isNotEmpty(jsonParser.getText())){ return format.parse(jsonParser.getText()); }else { return null; } } catch(Exception e) { System.out.println(e.getMessage()); throw new RuntimeException(e); } } }

在实体类的日期上使用注解：

@JsonDeserialize(using= DateJsonDeserializer.class)

@JsonSerialize(using= DateJsonSerializer.class)

privateDate time;