Game of Taking Stones （hdu5973）——2016大连现场赛C题 威佐夫博弈

Two people face two piles of stones and make a game. They take turns to take stones. As game rules, there are two different methods of taking stones: One scheme is that you can take any number of stones in any one pile while the alternative is to take the same amount of stones at the same time in two piles. In the end, the first person taking all the stones is winner.Now,giving the initial number of two stones, can you win this game if you are the first to take stones and both sides have taken the best strategy?

InputInput contains multiple sets of test data.Each test data occupies one line,containing two non-negative integers a andb,representing the number of two stones.a and b are not more than 10^100. OutputFor each test data,output answer on one line.1 means you are the winner,otherwise output 0. Sample Input

2 1
8 4
4 7

Sample Output

0
1

0

给两堆石子，两个人轮流拿，可以从其中的一堆拿任意多数量，也可以从两堆中拿相同的数量，拿到最后一颗为胜利者

l这是一个威佐夫博弈的裸题，对于a，b（a

l（sqrt（5）+1）/2是黄金分割数

import java.math.BigDecimal;   import java.util.Scanner; public class Main{          public static void main(String args[]){     Scanner sc=new Scanner(System.in);     BigDecimal two=new BigDecimal(2);     BigDecimal three= new BigDecimal(3);     BigDecimal five=new BigDecimal(5);     BigDecimal l=two,r=three;     for(int i=0;i<500;i++){     BigDecimal mid=l.add(r).divide(two);     if(mid.multiply(mid).compareTo(five)<0)     l=mid;     else     r=mid;         }     BigDecimal gold=l.add(BigDecimal.ONE).divide(two);//黄金分割数     BigDecimal a,b;     while(sc.hasNext()){     a=sc.nextBigDecimal();     b=sc.nextBigDecimal();     if(a.compareTo(b)>0){     BigDecimal tmp=a;     a=b;b=tmp;     }     b=b.subtract(a).multiply(gold);     b=b.setScale(0,BigDecimal.ROUND_DOWN);     if(a.compareTo(b)==0)     System.out.println("0");     else     System.out.println("1");     }         } }