根据经纬度求两点间距离

http://www.cnblogs.com/xionglee/articles/1493276.html

public static double DistanceOfTwoPoints(double lng1,double lat1,  double lng2, double lat2, GaussSphere gs)
        {            
            double radLat1 = Rad(lat1);
            double radLat2 = Rad(lat2);
            double a = radLat1 - radLat2;
            double b = Rad(lng1) - Rad(lng2);
            double s = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a / 2), 2) +
             Math.Cos(radLat1) * Math.Cos(radLat2) * Math.Pow(Math.Sin(b / 2), 2)));
            s = s * (gs == GaussSphere.WGS84 ? 6378137.0 : (gs == GaussSphere.Xian80 ? 6378140.0 : 6378245.0));
            s = Math.Round(s * 10000) / 10000;
            return s;
        }
        
        private static double Rad(double d)
        {
            return d * Math.PI / 180.0;
        }

    GaussSphere 为自定义枚举类型
    /// 

    /// 高斯投影中所选用的参考椭球
    /// 
    public enum GaussSphere
    {
        Beijing54,
        Xian80,
        WGS84,
    }

　　

转载于:https://www.cnblogs.com/blogsme/archive/2013/03/05/2943978.html