Problem 43 Sub-string divisibility (暴力...)

Sub-string divisibility

Problem 43

The number, 1406357289, is a 0 to 9 pandigital number because it is made up of each of the digits 0 to 9 in some order, but it also has a rather interesting sub-string divisibility property.

Let d1 be the 1st digit, d2 be the 2nd digit, and so on. In this way, we note the following:

  • d2d3d4=406 is divisible by 2
  • d3d4d5=063 is divisible by 3
  • d4d5d6=635 is divisible by 5
  • d5d6d7=357 is divisible by 7
  • d6d7d8=572 is divisible by 11
  • d7d8d9=728 is divisible by 13
  • d8d9d10=289 is divisible by 17

Find the sum of all 0 to 9 pandigital numbers with this property.


Answer:
16695334890
Completed on Sun, 30 Oct 2016, 07:48

题解:无脑暴力....

代码:

#include
using namespace std;

int main()
{
	long long a[10]={0,1,2,3,4,5,6,7,8,9};
	int ans=0;
	unsigned long long sum=0;
	do
	{
		if((a[1]*100+a[2]*10+a[3])%2==0)
		{
			if((a[2]*100+a[3]*10+a[4])%3==0)
			{
				if((a[3]*100+a[4]*10+a[5])%5==0)
				{
					if((a[4]*100+a[5]*10+a[6])%7==0)
					{
						if((a[5]*100+a[6]*10+a[7])%11==0)
						{
							if((a[6]*100+a[7]*10+a[8])%13==0)
							{
								if((a[7]*100+a[8]*10+a[9])%17==0)
								{
									ans++;
									sum+=(a[0]*1000000000+a[1]*100000000+a[2]*10000000+a[3]*1000000);
									sum+=(a[4]*100000+a[5]*10000+a[6]*1000+a[7]*100+a[8]*10+a[9]);
									cout<


你可能感兴趣的:(Project,Euler,ACM_暴力穷举)