C++中string类型与char *类型转换

1.string类型转换为char *

(1)使用stringstream进行转换

代码为：

#include
#include
#include
#include

using namespace std;
int main(int argc, char *argv[])
{
      stringstream sstr;
      sstr.clear();
      char * ch = new char[1024];
      string s="abcd";
      sstr<       sstr>>ch;
      cout<

      return 0;
}

(2)运用basic_string::c_str转换

1）函数原型：const value_type *c_str( ) const;

2）函数描述：

Converts the contents of a string as a C-style, null-terminated string.

将一个字符串的内容转化为一个c风格字符串的指针。

3）代码为：

 

// basic_string_c_str.cpp
// compile with: /EHsc
#include 
#include 

int main( ) 
{
   using namespace std;

   string  str1 ( "Hello world" );
   cout << "The original string object str1 is: " 
        << str1 << endl;
   cout << "The length of the string object str1 = " 
        << str1.length ( ) << endl << endl;

   // Converting a string to an array of characters
   const char *ptr1 = 0;
   ptr1= str1.data ( );
   cout << "The modified string object ptr1 is: " << ptr1 
        << endl;
   cout << "The length of character array str1 = " 
        << strlen ( ptr1) << endl << endl;

   // Converting a string to a C-style string
   const char *c_str1 = str1.c_str ( );
   cout << "The C-style string c_str1 is: " << c_str1 
        << endl;
   cout << "The length of C-style string str1 = " 
        << strlen ( c_str1) << endl << endl;
}

4)运行结果：

The original string object str1 is: Hello world
The length of the string object str1 = 11

The modified string object ptr1 is: Hello world
The length of character array str1 = 11

The C-style string c_str1 is: Hello world
The length of C-style string str1 = 11

2.char *类型转换为字符串string型

#include

#include

using namespace std;

int main()

{

       string str = "hello world";

       char * ch = 0;

       //one method

       strcpy(ch,str.c_str());    //即可

       cout << ch << endl;

      //another method

       for(int  i = 0; i < str.length();i ++ )

       {

             ch = str.at(i);

             ch++;

       }

//    system("pause");

       return 0;

}