LintCode：旋转链表

给定一个链表，旋转链表，使得每个节点向右移动k个位置，其中k是一个非负数

您在真实的面试中是否遇到过这个题？ 

Yes

样例

给出链表1->2->3->4->5->null和k=2

返回4->5->1->2->3->null

标签 Expand  

相关题目 Expand 

/**
* Definition for singly-linked list.
* public class ListNode {
*     int val;
*     ListNode next;
*     ListNode(int x) {
*         val = x;
*         next = null;
*     }
* }
*/
public class Solution {
    /**
     * @param head: the List
     * @param k: rotate to the right k places
     * @return: the list after rotation
     */
    public ListNode rotateRight(ListNode head, int k) {
        // write your code here
         if(head == null ) return null;
         ListNode c = head;
         int count = 0;
         while(c!=null){
              count++;
              c = c.next;
         }
         ListNode x = head;
         ListNode res = new ListNode(-1);
         ListNode  y  =   res;       
         ListNode front = new ListNode(-1);
         ListNode  z  =   front;
         for(int i=0;i