492. Construct the Rectangle

For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.

3. The difference between length L and width W should be as small as possible.
   You need to output the length L and the width W of the web page you designed in sequence.
   Example:
   Input: 4
   Output: [2, 2]
   Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
   But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal ccompared to [2,2]. So the length L is 2, and the width W is 2.

翻译 说了这么一堆 其实就是让你将一个数分解成两个乘数，找到相差最小的两个乘数。

考虑一种最佳情况，当N可以被开方时，明显的是这个数的开方，相差是0，于是推广到一般来说，想要两个数最小，肯定是从开方找起的。

class Solution {
    public int[] constructRectangle(int area) {
        int[] result = new int[2];
        for(int i = (int)Math.sqrt(area);i>=1;i--)
        {
            if(area%i==0)
            {
                result[0]=i>area/i? i:area/i;
                result[1]=i