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cstdlib
poj2181
简单dp View Code #include < iostream > #include <
cstdlib
·
2015-11-07 12:19
poj
poj2155
#include <iostream> #include <
cstdlib
> #include <cstring> #include <cstdio>
·
2015-11-07 12:18
poj
hdu1083完备匹配的判定
hdu1083/win.cpp * Created on: 2012-8-16 * Author : ben */ #include <cstdio> #include <
cstdlib
·
2015-11-07 12:04
HDU
模板:abs用法
例如:#include <
cstdlib
>对应 #include <
·
2015-11-07 12:45
模板
TSP-旅行商问题
#include <iostream> #include <cstring> #include <
cstdlib
> #include <climits>
·
2015-11-07 11:31
问题
Implementation:Segment Tree 线段树
参照书上写了一个,虽然不多,但是渣渣也写的很是费力 #include <iostream> #include <
cstdlib
> #incl
·
2015-11-07 11:30
tree
poj 2034 Anti-prime Sequences
注意如果开始时连续数小于d时也要是合数; 用DFS暴力搜索; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:21
sequence
poj 1654 Area
求多边形的面积; View Code #include<iostream> #include<cstdio> #include<
cstdlib
> #
·
2015-11-07 11:20
poj
poj 1329 Circle Through Three Points
我们可以用直线相交做,也可以用向量做; 直线相交: View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:20
poi
poj 2954 Triangle
+ 边上的点的和/2 -1; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:18
poj
poj 1410 Intersection
;顶点给你的顺序不一定就是左上角到右下角; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:18
intersect
poj 3304 Segments
枚举所有顶点的连线的直线与所有线段是否有交点; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:17
poj
poj 2007 Scrambled Polygon
这个题就是求凸包; 极角排序: View Code View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:15
2007
poj 2074 Line of Sight
这个题可以从正面做,直接用叉积求出最大值; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:15
poj
poj 2398 Toy Storage
id=2318是一样的;这里就不解释了; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:09
poj
poj 1556 The Doors
长度作为两点之间的距离,这样就可以转化为图论的最短路问题; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:09
poj
poj 2318 TOYS
由于隔板已经排好序了那么我们只要从左至右暴力过去可以了,条件是叉积大于0; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:07
poj
poj 1466 Girls and Boys
这是一道求最大独立集的问题; View Code #include<iostream> #include<cstdio> #include<
cstdlib
&
·
2015-11-07 11:06
poj
poj 3041 Asteroids
以列为右边建图,这样建好后,就是一个裸的二分匹配; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:03
poj
HDU 2063 过山车
这是一道裸的二分匹配题: View Code #include<iostream> #include<cstdio> #include<
cstdlib
>
·
2015-11-07 11:02
HDU
poj 1094 Sorting It All Out
这是一道拓扑排序题; View Code #include<iostream> #include<cstdio> #include<
cstdlib
>
·
2015-11-07 11:01
sort
poj 3026 Borg Maze
3:利用kruscal生成最小生成树; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:01
poj
poj 1258 Agri-Net
一道简单的最小生成树问题: View Code #include<iostream> #include<cstdio> #include<
cstdlib
>
·
2015-11-07 11:00
poj
poj 2485 Highways
一道简单的最小生成树问题; View Code #include<iostream> #include<cstdio> #include<
cstdlib
>
·
2015-11-07 11:59
poj
poj 2240 Arbitrage
这题可以用bellman比较容易解决; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:58
poj
poj 1125 Stockbroker Grapevine
问你以哪个节点为起点时到所有的节点的最短路的最长路最短; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:57
broker
poj 3259 Wormholes
bellman算法; 这里要注意的是路是双向的; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:55
orm
poj 1860 Currency Exchange
该种币种的数值数; 注意:货币的兑换可以循环使用多次; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:54
Exchange
poj 2993 Emag eht htiw Em Pleh
2996的反过来求的;这个题注意的就是建图; View Code #include<iostream> #include<cstdio> #include<
cstdlib
·
2015-11-07 11:53
poj
ZOJ1029
贪心,考虑连廊的特殊性即可过了 #include <iostream> #include <
cstdlib
> using 
·
2015-11-07 10:45
ZOJ
ZOJ1025(简单贪心)
#include <iostream> #include <
cstdlib
> using namespace &
·
2015-11-07 10:44
ZOJ
ZOJ1331
#include < iostream > #include <
cstdlib
> using namespace
·
2015-11-07 10:39
ZOJ
Manacher模板
#include<iostream> #include<cstdio> #include<cstring> #include<
cstdlib
> #
·
2015-11-07 10:24
man
师范大学 e: skyscrapers
1 #include<iostream> 2 #include<stdio.h> 3 #include<cstring> 4 #include<
cstdlib
·
2015-11-07 09:01
rap
求N的因子之和。
5 6 #include<iostream> 7 #include<map> 8 #include<cstdio> 9 #include<
cstdlib
·
2015-11-07 09:54
poj1010
dfs View Code #include <iostream> #include <cstdio> #include <
cstdlib
> #include
·
2015-11-06 08:10
poj
poj2153
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:01
poj
poj2141
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:01
poj
poj2136
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:00
poj
poj2112
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:58
poj
poj2299
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:57
poj
poj2104
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:57
poj
poj2291
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:56
poj
poj2262
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:55
poj
poj2255
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:54
poj
poj2251
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:53
poj
poj2248
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:52
poj
poj2249
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:52
poj
poj2239
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:51
poj
poj2236
< iostream > #include < cstdio > #include <
cstdlib
·
2015-11-06 08:50
poj
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