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cstdio
第一个按位DP
1 #include < iostream > 2 #include <
cstdio
·
2015-11-13 02:26
dp
POJ 3160 Father Christmas flymouse 解题报告
一个经典的图DP,首先对无向图进行强联通分量缩点变成DAG,这样就可以在DAG上用拓扑序做DP 需要注意的是点权是有负数的情况为此WA无数次 附代码供后人参考 #include <
cstdio
·
2015-11-13 02:10
poj
2-sat模板 hoj1917
#include <iostream>#include <cstring>#include <
cstdio
>#include <algorithm>#include
·
2015-11-13 02:09
模板
状态压缩的搜索 Tianjin University 2010 ACM-ICPC Team Sellect Contest 2 1008解题报告
#include <iostream>#include <
cstdio
>#include <cstring>#include <queue>using namespace
·
2015-11-13 02:06
test
最小费用流模板
#include <iostream> #include <cstring> #include <
cstdio
> #include <algorithm
·
2015-11-13 02:03
模板
hdu 4730 We Love MOE Girls
AC代码: #include<iostream> #include<
cstdio
> #include<cstring> using namespace
·
2015-11-13 02:45
love
hdu 4737 A Bit Fun
AC代码: #include<iostream> #include<
cstdio
> #include<c
·
2015-11-13 02:37
HDU
hdu 2094
题目链接 这题目数据比较水,反EG:a b,b c,d e,e f,f e, 这题用并查集吧,我还不会呢 #include <
cstdio
> #include
·
2015-11-13 02:22
HDU
BNU 沙漠之旅
1、步骤最多只有4步,超过4步则退出 2、油的行程相加后的总和距离大于剩余距离时也退出 AC代码: #include<iostream> #include<
cstdio
·
2015-11-13 02:19
B
BNU Invading system
AC代码: #include<iostream> #include<
cstdio
> #include<algo
·
2015-11-13 02:13
System
hdu 2080
题目链接 纯数学题,很多种解法,我用了两种解法 根据x表示与x轴的夹角,tanx=y/x; #include <
cstdio
> #include <
·
2015-11-13 02:10
HDU
poj1974
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:23
poj
poj3602
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:22
360
poj3561
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:21
poj
poj3505
二者只能一个动完另一个动 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>
·
2015-11-13 02:20
poj
poj3458
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:20
poj
poj3300
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:19
poj
poj3158
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:18
poj
poj3183
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:18
poj
poj2864
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:17
poj
poj2664
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:16
poj
poj2579
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:16
poj
poj2535
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:15
poj
poj2501
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:14
poj
poj2365
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:13
poj
poj2163
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:11
poj
poj1939
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:10
poj
poj1877
注意要用c++,精度问题 注意有负数答案 View Code #include <iostream>#include <
cstdio
>#include <cstdlib
·
2015-11-13 02:09
poj
poj1750
简单题 注意有两个相同单词相邻的情况 View Code #include <iostream>#include <
cstdio
>#include <cstdlib
·
2015-11-13 02:08
poj
poj1575
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:07
poj
poj1484
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:06
poj
poj1248
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:06
poj
poj1972
简单题 View Code #include <iostream>#include <
cstdio
>#include <cstdlib>#include
·
2015-11-13 02:05
poj
poj 2114 Boatherds 树的分治
#include <iostream> #include <
cstdio
> #include <cstring> #include <algorithm&
·
2015-11-13 02:17
poj
uva 11796 - Dog Distance
#include<iostream> #include<
cstdio
> #include<cmath> #define eps 1e-8 #define max
·
2015-11-13 02:11
uva
SCOI 2011糖果
(都是接近常数); 要根据题意选取适当的形式; View Code 1 #include <
cstdio
>
·
2015-11-13 02:37
sc
hdu 1029(hash)
#include <algorithm> #include <
cstdio
> #include <cstring>
·
2015-11-13 02:53
hash
SPOJ DISUBSTR(字符串hash)
#include <iostream> #include <algorithm> #include <
cstdio
> #in
·
2015-11-13 02:52
substr
SPOJ DISUBSTR(后缀数组)
#include <iostream> #include <
cstdio
> #include <
·
2015-11-13 02:51
substr
[HDOJ]1014. Uniform Generator
#include < iostream > #include <
cstdio
> using namespace std
·
2015-11-13 02:57
generator
[HDOJ]1000.A + B Problem
Code: #include <
cstdio
> #include < iostream > using
·
2015-11-13 02:46
em
HDU4544 湫湫系列故事――消灭兔子
Code: #include <
cstdio
> #include <que
·
2015-11-13 01:56
HDU
HDU Good Numbers (热身赛2)
一道水题、找下规律就OK了、不过要注意特判一下0、因为0也是good number、这个把我坑惨了= =||| #include<iostream> #include<
cstdio
·
2015-11-13 01:44
number
UVA 1411 - Ants(二分图完美匹配)
要求一个黑点连接一个白点,而且全部线段都不相交 思路:二分图完美匹配,权值存负的欧几里得距离,这种话,相交肯定比不相交权值小,所以做一次完美匹配就能够了 代码: #include <
cstdio
·
2015-11-13 01:45
ant
BNUOJ 1011 人工智能?
注意有有小数出现 #include <iostream> #include <string> #include <cstdlib> #include <
cstdio
·
2015-11-13 01:43
人工智能
NYOJ 86 找球号(一)
#include <iostream> #include <algorithm> #include <
cstdio
> using nam
·
2015-11-13 01:25
OJ
NYOJ 370 波动序列
pid=370 #include <iostream> #include<
cstdio
> using namespace std
·
2015-11-13 01:12
序列
第七届河南省ACM A题
#include <iostream> #include<
cstdio
> using namespace std; int data[105]; int n,
·
2015-11-13 01:10
ACM
POJ 2386 Lake Counting
id=2386 DFS 的入门级题目....依次递归8个方向即可: #include <iostream> //#include<
cstdio
·
2015-11-13 01:09
count
NYOJ 58 最少步数
BFS穷举: #include <iostream> #include<queue> #include<utility> #include<
cstdio
·
2015-11-13 01:09
OJ
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