16进制数组转字符串

今天做东西要用这个，读出来的ID号是16进制的，但是返回给上层的是字符串，LINUX下的底层函数想不到。比如unsigned char temp[10]={0xAB,0XAB,0XAB,0XAB,0XDB,0XEB,0XAB,0XAC,0XAC,0xee};我要输出的就是这样子，底层传上来的不是ASCII码。蛋痛得很`其他资料也没找到，本来想用sprintf函数的。可是完全不对头。后面已经写了这个功能函数。

#include"stdio.h"
# include <stdlib.h>


#define DATA_LENGTH 20

//函 数 名：HexToAsc()
//功能描述：把16进制转换为ASCII
char IntToStr(unsigned char aChar){
	char ss;
	switch(aChar)
	{
		case 0: ss= '0';break;
		case 1: ss= '1';break;
		case 2: ss= '2';break;
		case 3: ss= '3';break;
		case 4: ss= '4';break;
		case 5: ss= '5';break;
		case 6: ss= '6';break;
		case 7: ss= '7';break;
		case 8: ss= '8';break;
		case 9: ss= '9';break;

		case 10: ss= 'A';break;
		case 11: ss= 'B';break;
		case 12: ss= 'C';break;
		case 13: ss= 'D';break;
		case 14: ss= 'E';break;
		case 15: ss= 'F';break;
		default:break;
	}
	//printf("%c\n",ss);
    return ss; 
} 
char * HexToString(unsigned char Hex[],unsigned char lenth)
{
	unsigned char i=0,j=0;
	unsigned char tema,temp;
	char *str=(char*)malloc(lenth*2);
	printf("Large:-----%d\n",lenth*2);
	for(i=0;i<lenth;i++)
	{
		tema=(Hex[i]>>4)&0x0F;
		printf("%d\n",tema);
		str[j]=IntToStr(tema);
		printf("i=%d, %c\n",i,str[j]);
		j++;
		temp=Hex[i]&0x0F;
		printf("%d\n",temp);
		str[j]=IntToStr(temp);
		printf("i=%d, %c\n",i,str[j]);
		j++;
	}
	str[j]='\0';
	printf("Large:--j=%d\n",j);
	for(i=0;i<lenth*2;i++)
	{
		printf("kkkkk:i=%d  ;str[i]:%c\n",i,str[i]);
	}
	printf("wqf:%s\n",str);
	return str;
}

void main()
{
	char *str=NULL;
	unsigned char temp[10]={0xAB,0XAB,0XAB,0XAB,0XDB,0XEB,0XAB,0XAC,0XAC,0xee};
	str=HexToString(temp,10);
	printf("%s\n",str);
}