Given a binary tree
struct TreeLinkNode { TreeLinkNode *left; TreeLinkNode *right; TreeLinkNode *next; }
Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL
.
Initially, all next pointers are set to NULL
.
Note:
For example,
Given the following perfect binary tree,
1 / \ 2 3 / \ / \ 4 5 6 7
After calling your function, the tree should look like:
1 -> NULL / \ 2 -> 3 -> NULL / \ / \ 4->5->6->7 -> NULL
/** * Definition for binary tree with next pointer. * struct TreeLinkNode { * int val; * TreeLinkNode *left, *right, *next; * TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {} * }; */ class Solution { public: void connect(TreeLinkNode *root) { if (root == NULL) { return; } queue<TreeLinkNode*> buf; buf.push(root); buf.push(NULL); TreeLinkNode *prev = NULL; while (true) { TreeLinkNode *front = buf.front(); if (prev) { prev->next = front; prev = front; } else { prev = front; } if (front == NULL) { if (buf.size() == 1) { break; } prev = NULL; buf.push(NULL); } else { if (front->left) { buf.push(front->left); } if (front->right) { buf.push(front->right); } } buf.pop(); } } };