CodeForces - 282A Bit++ （水）

CodeForces - 282A Bit++ Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u Submit Status Description The classic programming language of Bitland is Bit++. This language is so peculiar and complicated. The language is that peculiar as it has exactly one variable, called x. Also, there are two operations: Operation ++ increases the value of variable x by 1. Operation -- decreases the value of variable x by 1. A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains. A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains. You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed). Input The first line contains a single integer n(1 ≤ n ≤ 150) — the number of statements in the programme. Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order. Output Print a single integer — the final value of x. Sample Input Input 1 ++X Output 1 Input 2 X++ --X Output 0 Source Codeforces Round #173 (Div. 2) /题意：++表示自增1，--表示自减1 给你n个字符串，让你输出这n个字符串最后的计算结果。 #include<stdio.h> #include<string.h> #include<algorithm> #include<iostream> using namespace std; int judge(char *s) { int l=strlen(s); for(int i=0;i<l;i++) { if(s[i]=='+') return 1; if(s[i]=='-') return -1; } return 0; } char s[20]; int main() { int n; while(scanf("%d",&n)!=EOF) { int cnt=0; while(n--) { scanf("%s",s); cnt+=judge(s); } printf("%d\n",cnt); } return 0; }