POJ1005

POJ1005

/* poj1005-简单计算 题目大意：河水以半圆的形状侵蚀土地，每年50，问房子建在(x,y)处多少年会被侵蚀 解题思路： 在(x, y)处，面积为s = 1/2 * π * r^2 需要year = floor(s / 50 + 1) 输入输出： Sample Input 2 1.0 1.0 25.0 0.0 Sample Output Property 1: This property will begin eroding in year 1. Property 2: This property will begin eroding in year 20. END OF OUTPUT. */

#include<iostream>
using namespace std;

const double pi = 3.1415926535;

int main()
{
    int year;
    int N;      //input lines
    double area;

    cin >> N;
    for (int i = 1; i <= N; ++i)
    {
        double x, y;
        cin >> x >> y;
        area = 0.5 * pi * (x*x + y*y);
        year = (int)(area / 50.0 + 1.0);
        cout << "Property " << i << ": This property will begin eroding in year " << year << '.' << endl;
    }
    cout << "END OF OUTPUT." << endl;
}