leetcode之旅（11）-Integer to Roman

题目描述：

Given an integer, convert it to a roman numeral.

Input is guaranteed to be within the range from 1 to 3999.

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leetcode之旅（10）-Roman to Integer

思路：

当前这个数是否大于最大的权？若大于则循环判断有几个这样的权？若小于，则降低权进行判断，重复判断操作

代码：

public class Solution {
    public String intToRoman(int num) {
        int values[] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1 };    
        String numerals[] = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I" };    
        String result = "";    
        for (int i = 0; i < 13; i++)   
        {    
            while (num >= values[i]) //循环判断当前权值个数 
            {    
                num -= values[i];    

                result = result +numerals[i]; //append函数是向string 的后面追加字符或字符串。 
            }    
        }    
        return result;    

    }
}