ios程序异常退出时,发送邮件告知

1,首先在delegate文件里面- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions函数里面添加:

NSSetUncaughtExceptionHandler (&UncaughtExceptionHandler);

2,实现捕捉到异常时调用的函数(在@implementation之上):

void UncaughtExceptionHandler(NSException *exception) {
 NSArray *arr = [exception callStackSymbols];
 NSString *reason = [exception reason];
 NSString *name = [exception name];
  
 NSString *urlStr = [NSString stringWithFormat:@"mailto://[email protected]?subject=bug报告&body=xxx项目报告!<br><br><br>"
      "错误详情:<br>%@<br>--------------------------<br>%@<br>---------------------<br>%@",
      name,reason,[arr componentsJoinedByString:@"<br>"]];
  
 NSURL *url = [NSURL URLWithString:[urlStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
 [[UIApplication sharedApplication] openURL:url];
    NSLog(@"%@",url);
}




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