1.如何让Controller不返回视图?(比如仅执行一些数据库操作)
很简单,只要在Controller中定义一个void类型的public方法即可
01 public void DeleteData()
02 {
03 using (SQLiteConnection conn = new SQLiteConnection("Data Source=" + Server.MapPath(_dbFile)))
04 {
05 conn.Open();
06 SQLiteCommand cmd = conn.CreateCommand();
07 cmd.CommandText = "delete from Products";
08 cmd.ExecuteNonQuery();
09 }
10
11 //顺便给个sqlite使用事务的代码
12 //using (SQLiteConnection conn = new SQLiteConnection("Data Source=" + Server.MapPath(_dbFile)))
13 //{
14 //conn.Open();
15 //SQLiteTransaction t = conn.BeginTransaction();
16 //try
17 //{
18 //SQLiteCommand cmd = conn.CreateCommand();
19 //cmd.CommandText = "insert into Products(Name,CreateDate,UpdateDate) values(@Name,@CreateDate,@UpdateDate)";
20
21 //for (int i = 0; i < 50; i++)
22 //{
23 //cmd.Parameters.Clear();
24 //cmd.Parameters.AddWithValue("Name", i.ToString().PadLeft(5, '0'));
25 //cmd.Parameters.AddWithValue("CreateDate", DateTime.Now);
26 //cmd.Parameters.AddWithValue("UpdateDate", DateTime.Now);
27 //cmd.ExecuteNonQuery();
28 //}
29
30 //t.Commit();
31 //}
32 //catch
33 //{
34 //t.Rollback();
35 //}
36 //}
37 }
这样就行了,调用方法类似 : http://localhost/Product/DeleteData 即可
2.如何让视图返回纯文本或Xml?
view sourceprint?1 public ActionResult GetTxt()
2 {
3 return new ContentResult() { ContentType = "text/plain", ContentEncoding = Encoding.UTF8, Content = "Hello World!" };
4 }
如果要返回xml,把text/plain改为text/xml即可.
3.如何把DataTable传给视图?
虽然很多官方教程都是推荐使用强类型的视图,但是需求是千变万化的,如果确实要传递DataTable给视图,可参考下面这个做:
view sourceprint?01 public ActionResult Index()
02 {
03 DataTable tbl = new DataTable();
04 using (SQLiteConnection conn = new SQLiteConnection("Data Source=" + Server.MapPath(_dbFile)))
05 {
06 SQLiteDataAdapter da = new SQLiteDataAdapter("Select * from Products", conn);
07 da.Fill(tbl);
08 ViewData["data"] = tbl;
09 }
10 return View();
11 }
然后在视图上可以这样写:
view sourceprint?1 <%
2 DataTable tbl = ViewData["data"] as DataTable;
3 foreach (DataRow dr in tbl.Rows)
4 {
5 //...
6 }
7 %>
4.如何使用自定义控件(做为数据显示模板)?
创建一个Partial View(局部视图),内容可参考这样:
view sourceprint?01 <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl" %>
02 <%@ Import Namespace="System.Data" %>
03 <tr>
04 <td>
05 <%=(ViewData.Model as DataRow)["Id"] %>
06 </td>
07 <td>
08 <%=(ViewData.Model as DataRow)["Name"]%>
09 </td>
10 <td>
11 <%=(ViewData.Model as DataRow)["CreateDate"]%>
12 </td>
13 <td>
14 <%=(ViewData.Model as DataRow)["UpdateDate"]%>
15 </td>
16 </tr>
然后在主视图中可这样使用:
view sourceprint?01 <table>
02 <tr>
03 <th>
04 Id
05 </th>
06 <th>
07 Name
08 </th>
09 <th>
10 CreateDate
11 </th>
12 <th>
13 UpdateDate
14 </th>
15 </tr>
16 <%
17 DataTable tbl = ViewData["data"] as DataTable;
18 foreach (DataRow dr in tbl.Rows)
19 {
20 Html.RenderPartial("~/Views/Product/ProductData.ascx", dr);
21 }
22 %>
23 </table>
5.页面/视图之间如何跳转?
分二种情况:
void类型的action(即问题1中所说的不返回视图的action):
有且只有一种方法:
view sourceprint?1 Response.Redirect("/product/Index");
注意:
如果写成Redirect("/product/Index"); 编译也会通过,但是根本不会有效果,因为前面不加Response.则变成了Controller类的Redirect方法,这个是有返回值的,必须用return Redirect()调用才会有效果,但是该方法又是void类型的,不允许return,所以才说这是有且仅有的一种方法.
常规返回ActionResult的action:
方法就很多了:
view sourceprint?01 public ActionResult ShowView1()
02 {
03 Response.Redirect("ShowView2"); //方法1
04 //return Redirect("ShowView2"); //方法2
05 //return RedirectToAction("ShowView2"); //方法3
06 return View("ShowView2"); //方法4
07 }
08
09 public ActionResult ShowView2()
10 {
11 ViewData["data"] = "View2";
12 return View();
13 }
作者:菩提树下的杨过
出处:http://yjmyzz.cnblogs.com