根据节点值获取xml文件中循环节点的特定节点

xml文件test.xml代码如下：

<?xml version= '1.0' encoding='gb2312'?>
<weighData>
 <a>
  <b>111</b>
  <c>333</c>
 </a>
 <a>
  <b>222</b>
  <c>444</c>
 </a>
 <a>
  <b>555</b>
  <c>666</c>
 </a>
</weighData>

获取<b></b>节点的值为222的<a></a>节点，代码如下：

package com.zl.test;
import java.io.File;
import org.dom4j.Document;
import org.dom4j.Element;
import org.dom4j.io.SAXReader;

public class XmlTest {

 public static void main(String[] args) {
   File file = new File("D:/test.xml");
  try {
   SAXReader reader = new  SAXReader();
   Document document =reader.read(file);
   Element ele = (Element) document.selectSingleNode("//weighData/a[b='222']");
   if(ele!=null){
    System.out.println("=========="+ele.asXML());
   }else{
    System.out.println("=========="+null);
   }
  } catch (Exception e) {
   e.printStackTrace();
  }
 }
}

运行结果：

==========<a>
                              <b>222</b>
                              <c>444</c>
                       </a>