javascript表单提交

function toCaseDetail(caseId, backTo) {

    $("body").css("padding-top", parseInt(60) + 'px');
    var pageNo = $("#pageNo").val();
    if (pageNo == '' || pageNo == 'undefined') {
        pageNo = 1;
    }
    $("#caseForm1").find("input[name=caseId]").val(caseId);
    $("#caseForm1").find("input[name=backTo]").val(backTo);
    var url = "<s:url action='toCaseDetail' namespace='/console/engineer/ticket/ajax'/>";
    document.caseForm1.action = url;//caseForm1代表的是表单action
    document.caseForm1.submit();//代表的是将表单提交.
}

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