Leetcode数组day1

704 二分查找

注意点,左闭右闭

class Solution {
public:
    int search(vector<int>& nums, int target) {
    //整数类型的动态数组的引用。
        int left=0;
        int right = nums.size()-1;

        while (left <= right){
            int middle = (right+left)/2;
            if (nums[middle]>target){ //在左区间
                right = middle-1;       //right移动到middle左边一位
            }
            if (nums[middle]<target){//在右区间
                left = middle+1;    //left移动到middle右边
            }
            if (nums[middle]==target){
                return middle;
            }
        }
        return -1;

    }
};

27 移除元素

class Solution {//双指针法
public:
    int removeElement(vector<int>& nums, int val) {  
        int left = 0;
        int right = 0;
        while (right<nums.size()){
            if (nums[right]==val){  //快指针指向元素等于val
                right += 1;
            }
            else{
                nums[left] = nums[right];
                left += 1;
                right += 1;
            }
        }
        return left;
    }
};

977 有序数组的平方

class Solution {
public:
    vector<int> sortedSquares(vector<int>& nums) {
        int right=nums.size()-1;
        vector<int> result(nums.size(),0);//创建一个名为 reuslt的大小为nums.size()的数组,值为0
        int i=0,j=nums.size()-1;
        while(i<=j){
            if (nums[i]*nums[i]<nums[j]*nums[j]){
                result[right]=nums[j]*nums[j];
                j -= 1;
                right -= 1;
            }
            else{
                result[right] = nums[i]*nums[i];
                i += 1;
                right -= 1;
            }
        }
        return result;
    }
};

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